Answer:
122*
122 degrees
Step-by-step explanation:
m∠GEF is 13 less than 5 times m∠DEG and m∠DEF = 149*
Solution:
As per given data,
m∠GEF = 5m∠DEG - 13* … (i)
m∠DEF = 149* -> m∠GEF + m∠DEG = 149* .. (ii)
Substituting value of m∠GEF in (ii)
We get,
(5m ∠DEG - 13*) + m∠DEG = 149*
6m ∠DEG - 13* = 149*
6m ∠DEG = 149* + 13* = 162*
m∠DEG = * = 27*
Substituting value of m∠DEG in (i)
We get,
m∠GEF = 5(27*) - 13*
m∠GEF = 135* - 13* = 122*
Its basically 7 see there is nothing but the number 7 which means as to an expression its 7.
We have been given that fuel efficiency for a 2007 passenger car was 31.2 mi/gal and the same model of car, the fuel efficiency increased to 35.6 mi/gal in 2012. Also, the gas tank for this car holds 16 gallons of gas.
We need to write a function and graph a linear function that models the distance that each car can travel for a given amount of gas up to one tankful.
Let represent the functions as
and
where
and
represent the distances traveled by car in years 2007 and 2012 and x represents the number of gallons. Therefore, we can express the required functions as:

Domain of both these functions are [0,16] and ranges are [0,499.2] and [0,569.6] respectively for years 2007 and 2012.
The difference function will be:


Domain of this function is [0,16] and range is [0,67.2].
The graphs are shown below.