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SVEN [57.7K]
3 years ago
14

Question 6 1 pts

Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

$125.6

that is the procedure above .

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Complete the following graphic organizer and then to find the missing information
Travka [436]

a) 4  

b) 47

c) 225

d) 120/400

4 0
3 years ago
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If m angle GEF is thirteen less than five times m angle DEG and m angle DEF = 149º, find m angle GEF. ​
Nina [5.8K]

Answer:

122*

122 degrees

Step-by-step explanation:

m∠GEF is 13 less than 5 times m∠DEG and m∠DEF = 149*

Solution:

As per given data,

m∠GEF = 5m∠DEG - 13* … (i)

m∠DEF = 149* -> m∠GEF + m∠DEG = 149* .. (ii)

Substituting value of m∠GEF in (ii)

We get,

(5m ∠DEG - 13*) + m∠DEG = 149*

6m ∠DEG - 13* = 149*

6m ∠DEG = 149* + 13* = 162*

m∠DEG = * = 27*

Substituting value of m∠DEG in (i)

We get,

m∠GEF = 5(27*) - 13*

m∠GEF = 135* - 13* = 122*

7 0
3 years ago
The expression 7! is equal to which of the following
Sladkaya [172]
Its basically 7 see there is nothing but the number 7 which means as to an expression its 7.
8 0
3 years ago
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5. Emmanuel makes 82,000 as a software designer. Use the follow tax chart to find what he will pay in taxes this year.
Mekhanik [1.2K]
I think the answer is d
5 0
3 years ago
The fuel efficiency for a 2007 passenger car was 31.2 mi/gal. For the same model of car, the fuel efficiency increased to 35.6 m
Ierofanga [76]

We have been given that fuel efficiency for a 2007 passenger car was 31.2 mi/gal and the same model of car, the fuel efficiency increased to 35.6 mi/gal in 2012. Also, the gas tank for this car holds 16 gallons of gas.

We need to write a function and graph a linear function that models the distance that each car can travel for a given amount of gas up to one tankful.

Let represent the functions as d_{1}(x) and d_{2}(x)  where d_{1} and d_{2} represent the distances traveled by car in years 2007 and 2012 and x represents the number of gallons. Therefore, we can express the required functions as:

d_{1}(x)=31.2x \text{ and } d_{2}(x) = 35.6x

Domain of both these functions are [0,16] and ranges are [0,499.2] and [0,569.6] respectively for years 2007 and 2012.

The difference function will be:

f(x)=35.6x-31.2x\\
f(x)=4.2x

f(16)=4.2*16=67.2

Domain of this function is [0,16] and range is [0,67.2].

The graphs are shown below.


3 0
3 years ago
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