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Ainat [17]
3 years ago
15

Solve this system of linear equations. Separate

Mathematics
2 answers:
Igoryamba3 years ago
6 0
Since 8 is 1/3 of 24 we can multiply 16x-2y to get 48x-6y, now we can see the two equations equal to each other. So 48x-6y= 4x+5y and you combine like variables by doing the inverse operation so you’ll get 44x= 11y. Simplified, this is 4x= y. So, now you plug in 4x for the y variable in the first equation, so you’ll get 16x- 2(4x)= -8. Then you solve for x...
16x- 8x= -8
8x= -8
x= -1

Then you plug the -1 in for the x variable and then solve... so
16(-1)- 2y= -8
-16- 2y= -8
-2y= 8
y= -4

So, overall your answer will be x= -1, y= -4
amid [387]3 years ago
3 0

Answer:

the answer is 396 beacsue i followed yiur instucton on the note answer.

Step-by-step explanation:

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Find the coordinates of point p , that lies 2/3 of the way on the directed line segment ab where A ( -2,5) , B (4,9)
OleMash [197]

Answer:

(1,7)

Step-by-step explanation:

first find the slope

9-5/4-(-2)=4/6=2/3

5+2=7

-2+3=1

=(1,7)

6 0
3 years ago
Translate 4.5 times q divided by 9
grigory [225]

Answer:

All I can really do is state it differently <> 4.5q /9

4 0
3 years ago
Hey everyone i was trying to setup this problem but I’m stuck can someone tell me setup for number 15 and 16 explain if you can
STatiana [176]

Answer:

15. x = 10 3/11

16. ∠Q = 75°

Step-by-step explanation:

<h3>15.</h3>

The two base angles of the isosceles triangle are congruent, so both are 180°-8x. The sum of those, together with the apex angle, will be 180°.

... 2(180 -8x) + (5x -67) = 180

... 360 -16x +5x -67 = 180 . . . . . eliminate parentheses

... -11x = -113 . . . . . subtract 293

... x = 113/11 = 10 3/11

_____

<em>Note on the solution</em>

This value of x makes the interior base angles of the triangle be 97 9/11°. The apex angle is then -15 7/11°. The solution is correct—all the angles add up properly—but the geometry cannot exist.

_____ _____

<h3>16.</h3>

The approach is the same. The sum of the two congruent base angles and the apex angle is 180°.

... 2(2x+15) + x = 180

... 5x + 30 = 180

... x = (180 -30)/5 = 30

... (2x +15)° = (2·30 +15)° = 75° = angle Q

5 0
3 years ago
Please please help!!
shepuryov [24]

Answer:

\large\boxed{x=0\ and\ x=\pi}

Step-by-step explanation:

\tan^2x\sec^2x+2\sec^2x-\tan^2x=2\\\\\text{Use}\ \tan x=\dfrac{\sin x}{\cos x},\ \sec x=\dfrac{1}{\cos x}:\\\\\left(\dfrac{\sin x}{\cos x}\right)^2\left(\dfrac{1}{\cos x}\right)^2+2\left(\dfrac{1}{\cos x}\right)^2-\left(\dfrac{\sin x}{\cos x}\right)^2=2\\\\\left(\dfrac{\sin^2x}{\cos^2x}\right)\left(\dfrac{1}{\cos^2x}\right)+\dfrac{2}{\cos^2x}-\dfrac{\sin^2x}{\cos^2x}=2

\dfrac{\sin^2x}{(\cos^2x)^2}+\dfrac{2-\sin^2x}{\cos^2x}=2\\\\\text{Use}\ \sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-(1-\cos^2x)}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-1+\cos^2x}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{1+\cos^2x}{\cos^2x}=2

\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{(1+\cos^2x)(\cos^2x)}{(\cos^2x)^2}=2\qquad\text{Use the distributive property}\\\\\dfrac{1-\cos^2x+\cos^2x+\cos^4x}{\cos^4x}=2\\\\\dfrac{1+\cos^4x}{\cos^4x}=2\qquad\text{multiply both sides by}\ \cos^4x\neq0\\\\1+\cos^4x=2\cos^4x\qquad\text{subtract}\ \cos^4x\ \text{from both sides}\\\\1=\cos^4x\iff \cos x=\pm\sqrt1\to\cos x=\pm1\\\\ x=k\pi\ for\ k\in\mathbb{Z}\\\\\text{On the interval}\ 0\leq x

4 0
3 years ago
What is the digit in the ten billions place in this number 30,242,386,651
Minchanka [31]
It’s 1 that’s in the ten billions
8 0
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