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alexandr1967 [171]
3 years ago
9

Difference between the hydrocarbons...Need help asap​

Chemistry
1 answer:
dsp733 years ago
5 0

<u>Explanation:</u>

Hydrocarbons are defined as organic compounds which are only made from carbon and hydrogen atoms.

There are mainly 3 types of hydrocarbons:

  • Alkanes are the type of hydrocarbons where a single bond is present between the carbon atoms. The general formula for these is C_nH_{2n+2}, where 'n' is the number of carbon atoms.
  • Alkenes are the type of hydrocarbons where at least one double bond is present between the carbon atoms. The general formula for these is C_nH_{2n}, where 'n' is the number of carbon atoms.
  • Alkynes are the type of hydrocarbons where at least one triple bond is present between the carbon atoms. The general formula for these is [tex]C_nH_{2n-2}, where 'n' is the number of carbon atoms.
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The addition of an inert gas has no effect on the equilibrium position of a gaseous reaction because ______. Multiple choice que
boyakko [2]

Inert gas does not affect the equilibrium position:

It is because the partial pressures of the reaction components remain the same.

What is Inert Gas?

  • Under a given set of conditions, an inert gas is a gas that does not undergo chemical reactions.
  • The noble gases (helium, neon, argon, krypton, xenon, and radon) were previously known as "inert gases" due to their perceived lack of involvement in any biochemical processes.
  • Because inert gases are non-reactive, they do not affect equilibrium partial pressures and thus do not affect volume.
  • An inert gas does not react with the reactants or products; it does not change the concentration of the products and reactants. Furthermore, because the volume is constant, the concentrations are unaffected. As a result, this does not affect equilibrium.

The equilibrium position won't change if an inert gas is added. A volume change won't change the equilibrium position if the total moles of gas in the products and reactants are the same. When the volume is reduced, the process changes to create fewer moles of gas.

Learn more about the inert gas here,

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5 0
2 years ago
Q1- Classify each of the molecules given below by molecular geometry.
Ludmilka [50]
It would be carbon dioxide codd2 for the molecules
3 0
2 years ago
Chlorine gas reacts with aluminum metal producing aluminum chloride. What mass of chlorine reacts with 9.00g of Al to form AlCl3
Anit [1.1K]
The  mass of  chlorine   that react  with  9.00 g  of Al to form AlCl3  is   35.465  grams

     Explanation
write  the equation  for  reaction
that is
2 Al +  3 Cl2  = 2 Al CL3
find  the moles  of    Al  reacted

moles = mass/molar mass

  9 g/ 27  g/mol = 0.333  moles  of Al

by use  of mole ratio between   Al to  Cl2    which is  2:3   find the moles of  Cl2

mole  of cl2 =  0.333 x3/2 = 0.4995  moles


mass of  Cl2  is therefore =  moles  x  molar mass

= 0.4995  x71 =  35.465  moles




6 0
4 years ago
What is the change in energy ?e of the hydrogen atom as the electron makes the transition from the n=3 energy level to the n=1 e
Contact [7]
The change in energy is is  known as work-energy
5 0
3 years ago
g Ethanol boils at 78.4 °C with \DeltaΔHvap = 38.6 kJ/mol. A 0.200-mol sample of ethanol is heated from some colder temperature
andrezito [222]

Answer:

8.77 kilo Joules  will be the total amount of heat required for both the heating and the vaporizing.

Explanation:

Moles of ethanol of ethanol = 0.200 mol

Heat required to heat 0.200 moles of ethanol = Q = 1.05 kJ

Enthalpy of vaporization of ethanol = \Delta H_{vap}=38.6 kJ/mol

Heat required to vaporize 0.200 moles of ethanol = Q'

Q'=\Delta H_{vap}\times 0.200 mol=38.6 kJ/mol\times 0.200 mol=7.72 kJ

Total heat required to fore heating and the vaporizing :

= Q + Q' = 1.05 kJ + 7.72 kJ = 8.77 kJ

8.77 kilo Joules  will be the total amount of heat required for both the heating and the vaporizing.

7 0
4 years ago
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