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2 years ago

What is stationary in science?

Chemistry

1 answer:

Reptile [31]2 years ago

4 0

Answer:

Standing still not movable

Explanation:

Meaning that it has stayed the same

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Burning 12.00 g of an oxoacid produces 17.95 g of carbon dioxide and 4.87 g of water. Consider that 0.25

Veseljchak [2.6K]

Answer: The molecular formula will be $C_6H_6O_6$

Explanation:

Mass of $CO_2$ = 17.95 g

Mass of $H_2O$ = 4.87 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 17.95 g of carbon dioxide, = $\frac{12}{44}\times 17.95=4.89g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 4.87 g of water, = $\frac{2}{18}\times 4.87=0.541g$ of hydrogen will be contained.

Mass of oxygen in the compound = (12.00) - (4.89+0.541) = 6.57 g

Mass of C = 4.89 g

Mass of H = 0.541 g

Mass of O = 6.57 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{4.89g}{12g/mole}=0.407moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.541g}{1g/mole}=0.541moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{6.57g}{16g/mole}=0.410moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.407}{0.407}=1$

For H = $\frac{0.541}{0.407}=1$

For O = $\frac{0.410}{0.407}=1$

The ratio of C : H : O = 1: 1 : 1

Hence the empirical formula is $CHO$ .

Hence the empirical formula is $CHO$

The empirical weight of $CHO$ = 1(12)+1(1)+1(16)= 29 g.

If 0.25 moles has mass of 44.0 g

Thus 1 mole has mass of = $\frac{44.0}{0.25}\times 1=176g$

Thus molecular mass is 176 g

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{176g}{29g}=6$

The molecular formula will be= $6\times CHO=C_6H_6O_6$

5 0

3 years ago

What is the hydroxide-ion concentration in a solution formed by combining 200. ml of 0.16 m hcl with 300. ml of 0.091 m naoh at

iren2701 [21]

34 degrees long that way you pass the exam

8 0

3 years ago

Ch3-ch=ch2-->br2/nacl

attashe74 [19]

CH3-CH=CH2+Br2--->CH3-CH(Br)-CH2-Br

8 0

3 years ago

Calculate the ph of 0,24 m of kch3coo.?

Galina-37 [17]

Answer:

Correct option is A)

KaC

1.8×10

−6

=1.34×10

−3

pH=−log[H

]

=2.88

Explanation:

here is your answer if you like my answer please follow

6 0

2 years ago

a solution containing 80 g of KCL in 200 g of H2O at 50 degrees celcius is cooled to 20 degrees celcius. How many grams of KCL r

Varvara68 [4.7K]

Answer:

12g KCl will be crystallized

Explanation:

To solve this problem you need to know solubility of KCl in water at 20°C is 34g per 100g of water.

That means the maximum concentration of KCl you can dissolve at 20°C in 200g of water is 34g×2 = 68g of KCl

As solution containing 80g of KCl, the extra KCl will be crystallized after cooling, that is:

80g of KCl - 68g of KCl = <em>12g KCl will be crystallized</em>

I hope it helps!

8 0

3 years ago

What is stationary in science?​

What is stationary in science?