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3 years ago

What is the pressure, in mm Hg, of 2.50 moles of an ideal gas if it has a volume of 50.0 liters when the temperature is 27.0° C?

1 answer:

8 0

Use the ideal gas law:
PV=nRT
p = pressure
v = volume
n = number of moles of sample
R = ideal gas constant = ~0.08206 (l*atm)/(K*mole)
T = Temp in Kelvin

Now we substitute while simultaneously solving for P(pressure)
P = (nRT)/V
P = (2.50 * 0.08206 * (27+273.15)) / 50
P = Now it's your turn.

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Sentence for death rate

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3 years ago

Gravity on Earth is 9.8 m/s2, and gravity on the Moon is 1.6 m/s2.

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Answer:

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Explanation:

First of Mass is the same in any sort of gravity. Now let's calculate weight

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where W = Weight

M = Mass

G = Gravity

W = (40kg)(1.6)

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2 years ago

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Answer:

Explanation:

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3 years ago

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A 33.0 mL sample of 1.15 M KBr and a 59.0 mL sample of 0.660 M KBr are mixed. The solution is then heated to evaporate water unt

Oksi-84 [34.3K]

Answer:

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

Explanation:

Step 1: Data given

Sample 1: The 1.15 M sample has a volume of 33.O mL

Sample 2: The 0.660 M sample has a volume of 59.0 mL

Molar mass of KBr = 119 g/mol

Molar mass of AgNO3 = 169.87 g/mol

Step 2: Calculate number of moles for both samples

Number of moles = Molarity * Volume

Sample 1: 1.15 M * 33 *10^-3 L = 0.03795 moles

Sample 2: 0.660 M *59*10^-3 L = 0.03894 moles

Total mol KBr = 0.03795 + 0.03894 = 0.07689 moles

Step 3: Calculate total mass

mass = Number of moles * Molar mass

mass = 0.07689 moles * 119 g/moles = 9.15 grams ( in 55mL)

Step 4: Calculate moles of AgBr

AgNO3 reacts with KBr

KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq)

1 mole of KBr consumed, needs 1 mole of AgNO3 to produce 1 mole of AgBr and 1 mole of KNO3

So 0.07689 moles of KBr wll need 0.07689 moles of AgNO3

Step 5: Calculate mass of silver nitrate

mass of AgNO3 = Moles of AgNO3 * Molar mass of AgNO3

mass of AgNO3 = 0.07689 moles * 169.87 g/mol = 13.06 grams

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

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3 years ago

An iron ore contains 39% Fe2O3 by mass. What is the maximum mass of iron that can be recovered from 13.2 kg of this ore?

Mars2501 [29]

Answer:

3.6036

Explanation:

0.39 * 13.2 = 5.148

5.148 * 0.7 = 3.6036

Fe2O3 = 0.7

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3 years ago