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xz_007 [3.2K]
3 years ago
11

Each point on the coordinate plane has an address called

Mathematics
1 answer:
RideAnS [48]3 years ago
8 0
I do not understand what to do , more explicitly sorry :(
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The wheel on a car completes
mars1129 [50]

Answer:

Step-by-step explanation:

Let d be the diameter of the wheel.

Circumference = πd

(35.325 m)/(25 revolutions) = (1.413 m)/revolution

πd = 1.413

d = 1.413/π = 0.45 m

4 0
3 years ago
If angle 1 and angle 2 are supplementary angles, and angle 3 and angle 2 are supplementary angles, what do you know about angle
dusya [7]

Answer:

  angle 1 and angle 3 are congruent

Step-by-step explanation:

Angles supplementary to the same angle are congruent. Here both angles 1 and 3 are supplementary to angle 2, so angles 1 and 3 are congruent.

_____

If you like, you can get there algebraically:

  m∠1 + m∠2 = 180

  m∠3 + m∠2 = 180

Subtract the second equation from the first:

  (m∠1 + m∠2) - (m∠3 + m∠2) = (180) - (180)

  m∠1 -m∠3 = 0 . . . . simplify

  m∠1 = m∠3 . . . . . . add m∠3

When angle measures are the same, the angles are congruent.

  ∠1 ≅ ∠3

4 0
3 years ago
Find the horizontal​ asymptote, if​ any, of the graph of the rational function. ​f(x)=16x5x2+7​
frozen [14]
There is an app called math-way it helps you with these types of questions
3 0
2 years ago
3. Show that a circle with equation (x−2)^2+(y+3)^2=160 has two tangent lines with equations
Pepsi [2]

Answer:

  see below

Step-by-step explanation:

A graphing calculator shows each of the lines intersect the circle in exactly one place, so is tangent.

__

Each of the given lines is written in point-slope form. Each has a slope of 1/3. We will call the point in its equation the "reference point" of each line. For the first line, it is (6, -15); for the second line it is (-2, 9).

The center of the circle is (2, -3), so the slope from the center to the reference point of each line is ...

  line 1: (-15 -(-3))/(6 -2) = -12/4 = -3

  line 2: (9 -(-3))/(-2-2) = 12/-4 = -3

These slopes are the negative reciprocal of the slope of each of the lines, so a segment from the circle center to the reference point of each line is perpendicular to the line.

__

The reference point of line 1 (6, -15) is on the circle:

  (6 -2)^2 +(-15 +3)^2 = 16 +144 = 160

The reference point of line 2 (-2, 9) is on the circle:

  (-2-2)^2 +(9 +3)^2 = 16 +144 = 160

So, the reference point of each line is on the circle and that point is the endpoint of a segment from the circle center that is perpendicular to the line. Hence each of the lines is a tangent at its reference point.

6 0
3 years ago
ABC is rotated 180º using the origin as the center of rotation.
kogti [31]

Answer:

ejbf 1037 2049y 29rh

Step-by-step explanation:

jsu31j 2984 e84ube e94bg.

3 0
2 years ago
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