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Goshia [24]
3 years ago
8

About twice a day my Chromebook blacks out. why does it do that?

Computers and Technology
2 answers:
Veronika [31]3 years ago
7 0
Go to setting and change the time it cuts off mine does that to but i change it
Vika [28.1K]3 years ago
4 0
It happens to me also but not everyday
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2.5 lesson practice edhesive
VARVARA [1.3K]

Answer:

Huh,.......? what.....?

6 0
3 years ago
Read 2 more answers
Write, compile, and test a program named PersonalInfo that displays a person’s name, birthdate, work phone number, and cell phon
djverab [1.8K]

Answer:

A very simple C program is as follows:

#include <stdio.h>  // for input output functions

int main()  

 {

    printf("Name : John\n");   //display name

    printf("Date of Birth : 05/02/1993\n");  //displays DOB

    printf("Mobile Number: 98-7654321\n");  //displays mobile number

  }    

Explanation:

Now if you want to take name, date of birth and number from user as input then you can use the following code:

#include <iostream> // for input output functions

using namespace std; // to identify objects like cin cout

/* The function named PersonalInfo that takes input from user and displays name, mobile number and data of birth on output screen */

void PersonalInfo(char name[],char birthdate[], char number[]){

//prompts user to enter name

cout<<"Please enter your name: "<<endl;

cin>>name; //stores name entered by the user

//prompts user to enter his dob in the format given in the bracket

cout<<"Please enter your birthdate (dd/mm/yyyy): "<<endl;

cin>>birthdate; //stores dob entered by the user

//prompts user to enter his mobile number in the given format

cout<<"Please enter your mobile number (xx-xxx-xxxxxxx): "<<endl;

cin>>number; //holds the digits entered by the user

cout<<"Your name is: "<<name<<endl; //displays name

cout<<"Your birthdate is:"<< birthdate<<endl; //displays date of birth

cout<<"Your mobile number is: "<<number<<endl; } //displays number

int main() //start of main() function body

{   char username[30],dob[30],phone[30];

/*three char type arrays that contain name of user in username, date of birth in dob and phone number in phone array */

   PersonalInfo(username,dob,phone);  } //calls function PersonalInfo()

Output:

Please enter your name: John

Please enter your birthdate (dd/mm/yyyy): 09/05/1993

Please enter your mobile number (xx-xxx-xxxxxxx): 91-123-4567890

Your name is: John

Your birthdate is: 09/05/1993

Your mobile number is: 91-123-4567890

7 0
3 years ago
What is the generic name for a single piece of data
Snowcat [4.5K]

The correct answer is:    " datum " .

_________________________

4 0
4 years ago
In the range E7:E11, apply the Currency number format with zero decimal places and $ as the symbol.
lisabon 2012 [21]

Answer:

bt wheres the data

Explanation:

6 0
3 years ago
Write a function addOddMinusEven that takes two integers indicating the starting point and the end point. Then calculate the sum
snow_lady [41]

Answer:g

   public static int addOddMinusEven(int start, int end){

       int odd =0;

       int even = 0;

       for(int i =start; i<end; i++){

           if(i%2==0){

               even = even+i;

           }

           else{

               odd = odd+i;

           }

       }

       return odd-even;

   }

}

Explanation:

Using Java programming language:

  • The method addOddMinusEven() is created to accept two parameters of ints start and end
  • Using a for loop statement we iterate from start to end but not including end
  • Using a modulos operator we check for even and odds
  • The method then returns odd-even
  • See below a complete method with a call to the method addOddMinusEven()

public class num13 {

   public static void main(String[] args) {

       int start = 2;

       int stop = 10;

       System.out.println(addOddMinusEven(start,stop));

   }

   public static int addOddMinusEven(int start, int end){

       int odd =0;

       int even = 0;

       for(int i =start; i<end; i++){

           if(i%2==0){

               even = even+i;

           }

           else{

               odd = odd+i;

           }

       }

       return odd-even;

   }

}

8 0
3 years ago
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