1. B. Hemo is on a machine, peritoneal is in the abdomen
2. B. Nothing is as good as having your own kidney, and not everyone is a good candidate for all types of dialysis.
3. Also B. Peritoneal dialysis is done over a longer period of time, up to 24 hours. Hemodialysis is done in a few hours. Your kidney works 24/7.
Answer:
![\lambda'=78.086\ nm](https://tex.z-dn.net/?f=%5Clambda%27%3D78.086%5C%20nm)
Explanation:
Given:
- wavelength of light in the air,
![\lambda=530\times 10^{-9}\ m](https://tex.z-dn.net/?f=%5Clambda%3D530%5Ctimes%2010%5E%7B-9%7D%5C%20m)
- time taken to travel from the source to the photocell via air,
![t=16.7\ s](https://tex.z-dn.net/?f=t%3D16.7%5C%20s)
- time taken to reach the photocell via air and glass slab,
![t'=21.3\times 10^{-9}\ s](https://tex.z-dn.net/?f=t%27%3D21.3%5Ctimes%2010%5E%7B-9%7D%5C%20s)
- thickness of the glass slab,
![x=0.87\ m](https://tex.z-dn.net/?f=x%3D0.87%5C%20m)
<u>Now we have the relation for time:</u>
![\rm time=\frac{distance}{speed}](https://tex.z-dn.net/?f=%5Crm%20time%3D%5Cfrac%7Bdistance%7D%7Bspeed%7D)
hence,
![t=\frac{d}{c}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bc%7D)
c= speed of light in air
![16.7\times 10^{-9}=\frac{d}{3\times 10^8}](https://tex.z-dn.net/?f=16.7%5Ctimes%2010%5E%7B-9%7D%3D%5Cfrac%7Bd%7D%7B3%5Ctimes%2010%5E8%7D)
![d=16.7\times 10^{-9}\times 3\times 10^8](https://tex.z-dn.net/?f=d%3D16.7%5Ctimes%2010%5E%7B-9%7D%5Ctimes%203%5Ctimes%2010%5E8)
![d=5.01\ m](https://tex.z-dn.net/?f=d%3D5.01%5C%20m)
For the case when glass slab is inserted between the path of light:
(since light travel with the speed c only in the air)
here:
v = speed of light in the glass
![\frac{(5.01-0.87)}{3\times 10^8} +\frac{0.87}{v} =21.3\times 10^{-9}](https://tex.z-dn.net/?f=%5Cfrac%7B%285.01-0.87%29%7D%7B3%5Ctimes%2010%5E8%7D%20%2B%5Cfrac%7B0.87%7D%7Bv%7D%20%3D21.3%5Ctimes%2010%5E%7B-9%7D)
![v=4.42\times 10^7\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D4.42%5Ctimes%2010%5E7%5C%20m.s%5E%7B-1%7D)
Using Snell's law:
![\frac{\lambda}{\lambda'} =\frac{c}{v}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clambda%7D%7B%5Clambda%27%7D%20%3D%5Cfrac%7Bc%7D%7Bv%7D)
![\frac{530}{\lambda'} =\frac{3\times 10^8}{4.42\times 10^7}](https://tex.z-dn.net/?f=%5Cfrac%7B530%7D%7B%5Clambda%27%7D%20%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B4.42%5Ctimes%2010%5E7%7D)
![\lambda'=78.086\ nm](https://tex.z-dn.net/?f=%5Clambda%27%3D78.086%5C%20nm)
Answer:
D. 4000 km
Explanation:
f = Frequency of wave that is being transmitted = 76 Hz
= Wavelength of wave that is being transmitted
v = The velocity of electromagnetic waves through air = ![3\times 10^8\ m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8%5C%20m%2Fs)
Velocity of a wave is given by
![v=f\lambda\\\Rightarrow \lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{3\times 10^8}{76}\\\Rightarrow \lambda=3947368.42105\ m=3947.36842105 km\approx 4000\ km](https://tex.z-dn.net/?f=v%3Df%5Clambda%5C%5C%5CRightarrow%20%5Clambda%3D%5Cfrac%7Bv%7D%7Bf%7D%5C%5C%5CRightarrow%20%5Clambda%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B76%7D%5C%5C%5CRightarrow%20%5Clambda%3D3947368.42105%5C%20m%3D3947.36842105%20km%5Capprox%204000%5C%20km)
Hence, the approximate wavelength of the waves is 4000 km