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blondinia [14]
2 years ago
11

according to isaac newtons theory of gravitation the force exerted between two objects is dependent on- A- an objects weight. B-

objects energy. C object volume. D- objects mass
Physics
1 answer:
puteri [66]2 years ago
3 0
A an objects weight hope this helps! :D 
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A 7.0-kg rock is subject to a variable force given by the equation f(x)=6.0n−(2.0n/m)x+(6.0n/m2)x2 if the rock initially is at r
stealth61 [152]
For Newton's second law, the force is equal to the product between the mass and the acceleration of the rocket:
F=ma
From which we can rewrite the acceleration as
a(x)= \frac{F}{m} =  \frac{1}{m} (6-2x+6x^2)
where m=7.0 kg.

The velocity of the rocket is the derivative of the acceleration:
v(x) =  \frac{1}{m} (-2+12 x)
and if we substitute x=9.0 m, we find the rocket velocity after 9.0 m:
v(9)= \frac{1}{7}(-2+12\cdot 9)=15.1 m/s

4 0
3 years ago
1. In a series circuit, if one bulb goes out the other blubs will stay lit.
RideAnS [48]
I think is False
I think is False
5 0
3 years ago
Read 2 more answers
In the design of a supermarket, there are to be several ramps connecting different parts of the store. Customers will have to pu
tatuchka [14]

Answer:

3.90 degrees

Explanation:

Let g= 9.81 m/s2. The gravity of the 30kg grocery cart is

W = mg = 30*9.81 = 294.3 N

This gravity is split into 2 components on the ramp, 1 parallel and the other perpendicular to the ramp.

We can calculate the parallel one since it's the one that affects the force required to push up

F = WsinΘ

Since customer would not complain if the force is no more than 20N

F = 20

294.3sin\theta = 20

sin\theta = 20/294.3 = 0.068

\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0

So the ramp cannot be larger than 3.9 degrees

6 0
3 years ago
If you quadruple the temperature of a black body, by what factor will the total energy radiated per second per square meter incr
arlik [135]

<u>In modern physics</u>, as it was called "Stefan-Boltzmann law", the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of the black body's temperature T

as:

P\alpha T^4

where: P is the power (total energy radiated per second per square meter) and T is the temperature of a black body.

then we can make a ratio between the state of before quadruple (with subscript 1) and after (with subscript 2) as:

\frac{P_{1} }{P_{2} } =\frac{T_{1}^4 }{T_{2}^4}

As

T_{2}=4T_{1}

Then

\frac{P_{1} }{P_{2} } =\frac{T_{1}^4 }{(4T_{1})^4}

then

P_{2}=256*P_{1}

  • The factor will the total energy radiated per second per square meter increase = 256
5 0
3 years ago
A 45.2-kg person is on a barrel ride at an amusement park. She stands on a platform with her back to the barrel wall. The 3.74-m
elena-14-01-66 [18.8K]

Answer:

  • <u><em>1,230N</em></u>

Explanation:

<u>1. Name of the variables:</u>

   f:frequency\\\\ \omega:angular\text{ }speed\\\\ a_c:centripetal\text{ }acceleration\\\\ F_c:centripetal\text{ }force\\ \\ m:mass\\ \\ d:diameter\\ \\ r:radius\\ \\ g:gravitational\text{ }acceleration

<u>2. Formulae:</u>

         f=\dfrac{number\text{ }of\text{ }revolutions}{time}

          \omega=2\pi f

          a_c=\omega^2 r

           F_c=m\times a_c

<u>3. Solution (calculations)</u>

       f=\dfrac{1}{1.65s}=0.\overline{60}s^{-1}

       \omega=2\pi\times0.\overline{60}\approx 3.808rad/s

      a_c=(3.808rad/s)^2\times (3.74/2m)=27.12m/s^2

      F_c=45.2kg\times27.12m/s^2=1,225.67N\approx 1,230N

3 0
3 years ago
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