A pipe branches symmetrically into two legs of length L, and the whole system rotates with angular speed ω around its axis of sy
mmetry. Each branch is inclined at angle α to the axis of rotation. Liquid enters the pipe steadily, with zero angular momentum, at volume flow rate Q. The pipe diameter, D, is much smaller than L. Obtain an expression for the external torque required to turn the pipe. What additional torque would be required to impart angular acceleration ω_ ?
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Answer:
Explanation:
The equation for the linear impulse is as follows:
where is impulse,
is the force, and
is the change in time.
The force, according to Newton's second law:
and since
the force will be:
replacing in the equation for impulse:
we see that is canceled, so
And according to the problem ,
and the mass of the passenger is
. Thus:
the magnitude of the linear impulse experienced the passenger is