Let
x = the number of a-cables
y = the number of b-cables
z = the number of c-cables
Cable a uses 3 black, 3 white and 2 red wires.
Cable b uses 1 black, 2 white and 1 red wire.
Cable c uses 2 black, 1 white and 2 red wires.
Because 120 black, 110 white and 100 red wires were used, therefore the system of equations is
3x + y + 2z = 120 (1)
3x + 2y + z = 110 (2)
2x + y + 2z = 100 (3)
Answer:
3x + y + 2z = 120
3x + 2y + z = 110
2x + y + 2z = 100
where
x,y,z = the number of a, b and c-cables respectively.
A = 1/4 * (pi) * d^2
A = 1/4 * (pi) * 8^2
A = 1/4 * (pi) * 64
A = 1/4(64) * (pi)
A = 64/4 * (pi)
A = 16 (pi) in^2
Your answer is 16 pi in^2
~Silver
15% of 80 is 12.
To check this, you can multiply 80 x 0.15, which gives you an answer of 12.
Answer:
5 ft.
Step-by-step explanation:
Since 1 foot is 12 inches, and you have to be 60 inches tall, than you would divide 60 by 12. which is 5. So it will be 5ft.
Okay so this means g(x) is 12 times f(x)
g(x)=f(12x)= 12(6x-10)
g(x)=72x-120