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lapo4ka [179]
3 years ago
13

What is the percent of change from 800,000 to 600,000?

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0
I'm pretty sure it's 75%
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The base of a rectangle prism is 20 cm. If the height of the prism is 5 cm what is it volume
goldenfox [79]

Answer:

Answer : 100^3

Step-by-step explanation:

formula to find volume of prism =

v = base area * height

v = 20 * 5

v = 100

so , volume is 100^3

7 0
3 years ago
THE RIGHT ANSWER WILL RECIEVE A BRAINLEST AND POINTS AND THANXS!!!
ExtremeBDS [4]
Sorry for the poor graph. The solution to the inequality is
x \leqslant - 5

4 0
3 years ago
Solve the equation<br><br> c/7=6 1/7
Softa [21]
c/7 = 6 1/7 ⇒ c = 43 ⇒ 43/7 = 6 1/7

Convert mixed fraction into a simple fraction

6 1/7 ⇒ (6 * 7 + 1)/7 = 43/7 

c/7 = 43/7

proportionality: 

a/b = c/d where    ad = bc

a = c 
b = 7 
c = 43
d = 7          

ad = bc ⇒ c7 = 7*43 ⇒ c7 = 301 ⇒ 7c/7 = 301/7 ⇒ c = 43

 
5 0
3 years ago
Read 2 more answers
The figure below shows the quotient of Fraction 3 over 4 divided by Fraction 3 over 8 .
Orlov [11]

Answer:

i think i know

Step-by-step explanation:

3 0
3 years ago
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There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
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