What is the expanded notation for 15,729

The graph of f(x) = x2 + x - 6 is shown below.

guapka [62]

Answer:

the solutions of a function are the points where for some value of x the function becomes zero

thus the solns for this graph would be

that's option 1.

3 0

2 years ago

Which equation has the same solutions as 2x^2+16x-10=0 a) (x+4)^2=-3 b) (x+4)^2=-11 c) (x+4)^2=13 d) (x+4)^2=21

ikadub [295]

I'm working on the same thing down load the algebra tiger it really helps a lot I promise I use it daily to help with these

4 0

2 years ago

Jose and two of his friends are collecting baseball cards. Their goal is for the three of them to collect at least 100 cards in

schepotkina [342]

Answer:

3c + 43 >_ 100

Step-by-step explanation:

7 0

2 years ago

Solve the equation x2 + + 7x= 30

antiseptic1488 [7]

Answer:

x^2+7x=30

x^2+7x-30=0

Here a=1,b=7 and c=-30

Now,

Discriminant(D)=b^2-4ac

=7^2-4×1×(-30)

=49+120=169

By applying Quadratic formula

x=-b+- root over b^2-4ac÷2a

=-7+- root over D ÷ 2×1

=-7 +- root over 169 ÷2

=-7 +- 13 ÷2

Now,

Either x=-7+13÷2=6÷2=3

Or x=-7 -13 ÷2=-20÷2=-10

Hence, ans is (C) x=-10 and x=3

8 0

3 years ago

The CEO of a large electric utility claims that more than 75 percent of his customers are very satisfied with the service they r

vichka [17]

Answer:

$z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462$

Now we can find the p value using the alternative hypothesis with this probability:

$p_v =P(z>0.462)=0.322$

Since the p value is large enough, we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

Step-by-step explanation:

Information provided

n=100 represent the random sample selected

$\hat p=0.77$ estimated proportion of students that are satisfied

is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if more than 75 percent of his customers are very satisfied with the service they receive, then the system of hypothesis is.:

Null hypothesis: $p\leq 0.75$

Alternative hypothesis: $p > 0.75$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462$

Now we can find the p value using the alternative hypothesis with this probability:

$p_v =P(z>0.462)=0.322$

Since the p value is large enough we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%

4 0

3 years ago