For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
Answer:
A. a testable scientific question
Answer:
Step-by-step explanation:
Given
Required
The inverse
Replace f(n) with y
Swap positions of y and n
Make y the subject
Replace y with f'(n)
Answer:
It’s b
Step-by-step explanation:
Answer:
y = -4/3 x=-1/3
Step-by-step explanation:
y = x2 + 2x – 3 and y = x – 1
y= (y + 1)2 + 2(y + 1) - 3 and x= y+ 1
y= 2y + 2 + 2y +2 and x= y+ 1
-3y = 4 and x= y+ 1
y = -4/3 and x = (-4/3) + 1 = -1/3
x2 is x squared or x multiplied by two
