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2 years ago

The radius of a circle is 4 feet. What is the area of a sector bounded by a 45 degree arc

Mathematics

2 answers:

Kipish [7]2 years ago

6 0

45/360 * 4^2 pi = 6.283
ANSWER IS 6.283 (3 decimal places)

alexgriva [62]2 years ago

3 0

Answer:

2π ft²

Step-by-step explanation:

Circle Area:

A = πr²

A = π × (4 ft)²

A = 16π ft²

Sector Area:

A = (45°)/(360°) × 16π ft²

A = 2π ft²

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Analyze the diagram below and complete the instructions that follow.

Drupady [299]

Answer:

Step-by-step explanation:

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3 years ago

A rectangular photograph is nine centimeters wide and fourteen centimeters long. The photograph is enlarged by increasing the le

koban [17]

Answer:

Width=13cm

Length=18cm

Step-by-step explanation:

Width of the Initial Photograph=9cm

Length of the Initial Photograph=14cm

If width and length are increased by an equal amount, say x

New Width=9+x

New Length=14+x

Area of the new photo is 108 square centimeters greater than the area of the original photo.

Area of Original Photo=14*9=126cm²

Aeea of the New Photo=126+108=234cm²

Therefore:

(9+x)(14+x)=234

126+9x+14x+x²-234=0

x²+23x-108=0

x²+27x-4x-108=0

x(x+27)-4(x+27)=0

(x+27)(x-4)=0

x+27=0 or x-4=0

x=-27 or x=4

Since x≠-27

x=4cm

The dimensions of the new photo are:

Width=9+x=9+4=13cm

Length=14+x=14+4=18cm

4 0

2 years ago

Which expression is equivalent to 36^-1/2

inn [45]

ANSWER

$( {36})^{ (- \frac{1}{2}) } = \frac{1}{6}$

EXPLANATION

The given expression is

${36}^{( - \frac{1}{2} )}$
This is having a negative index. We must first of all change to a positive index.

Recall that,

${a}^{ - m} = \frac{1}{ {a}^{m} }$

We apply this law of exponents to get,

${36}^{( - \frac{1}{2} )} = \frac{1}{ {36}^{( \frac{1}{2} )} }$

We cab rewrite the given expression to obtain;

${36}^{( - \frac{1}{2} )} = \frac{1}{ \sqrt{36} }$

This will simplify to give us,

${36}^{( - \frac{1}{2} )} = \frac{1}{ 6 }$

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2 years ago

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sergij07 [2.7K]

54:36 is your answer.

If you need anymore help on ratios visit, “goodcalculators.com/ratio-calculator/

It should help

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2 years ago

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