Remark
The formula for this series is
t_n = n^2 - 1
Explanation
If the series ends at 288, then the highest value n can have is 17
So you would write t_n = n^2 - 1 {n| 1 ≤ n ≤17}
If you said this to someone, you would say "t_n = n squared minus 1 where n is such that 1 is greater than or equal to 1 or less than or equal to 17"
Example
What is the 4th term in this series?
t_4 = 4^2 - 1
t_4 = 16 - 1
t_4 = 15
A) multiply them
When you have a power of a power you multiply the powers together
It's equal multiple of 4 and 13
LCM = 4*13 = 52
Answer:
A) 6x + 6y = 24, Yes, they have the same solution set
Step-by-step explanation:
Let's first start by multiplying the equation by 3:
(2*3)x + (2*3)y = 24
6x + 6y = 24
Now lets find the solution set for both:
6y = -6x + 24
y = -x +4
2y = -2x + 8
y = -x +4
Yes, they have the same solution set
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