Answer:
Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.
Step-by-step explanation:
Given:
In Δ PQT
PQ = 30 ft
QT = 28 ft
TP = 20 ft
In Δ QRS
QR = 15 ft
RS = 14 ft
SQ = 10 ft
To Prove:
Δ PQT ~ Δ QRS
Proof:
First we consider the ratio of the sides
..............( 1 )
..............( 2 )
..............( 3 )
So By equation ( 1 ), ( 2 ) and ( 3 ) we get

Now in Δ PQT and Δ QRS we have

Which are corresponding sides of a similar triangle in proportion.
∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved
X=132
To find y
180-132= 48
180-68-48=64
y=64
We are given 2 sides 18.7, 16.1 and a NON-included angle.
We have to calculate the altitude of the triangle.
altitude = 18.7 * sine (35)
altitude = 18.7 * 0.57358
altitude =
<span>
<span>
<span>
10.725946
</span>
</span>
</span>
In this case, side c is greater than the altitude and is less than side a so 2 two triangles will be formed.
Source:
http://www.1728.org/trigssa.htm
ANSWER

EXPLANATION
The given bicycle has a tyre that is 28 inches in diameter.
How far the bicycle moves forward each time the wheel goes around is the circumference of the bicycle tyre.
This is calculated using the formula:

We substitute the diameter and


This simplifies to


Answer:
p/q = -5/25
multiply-25/5 × -5/25 You'll get the answer as 1.