All categories

3 years ago

Find the midpoint between two points on a coordinate plane whose coordinates are (5,7) and (-3,1)

Mathematics

2 answers:

hoa [83]3 years ago

4 0

Step-by-step explanation:

Mid point formula ,

x = (x1+x2)/2 , y = (y1+y2)/2

x = 1 , y = 4

therefore ,midpoint is (x, y)= (1,4)

defon3 years ago

3 0

(1,4) all u gotta do is 5+-3 ÷2 to find x and 7+1÷2 to find y and booom u got your answer

You might be interested in

Suppose you choose a marble from a bag containing 6 red marbles , 2 white marbles and 5 blue marbles you return the first marble

algol [13]

Answer:

30/169

Step-by-step explanation:

We need to know how many marbles in the bag

6 red marbles + 2 white marbles + 5 blue marbles = 13 marbles

P (red) = red / total = 6/13

We then put the marble bad so there are still 13 marbles in the bag

P(blue) = blue /total = 5/13

P (red then blue ) = P(red) *P(blue)

= 6/13 * 5/13 = 30/169

8 0

4 years ago

A shipping container will be used to transport several 70-kilogram crates across the country by rail. The greatest weight that c

alina1380 [7]

Subtract what has already been loaded from total amount allowed:

23500 - 9700 = 13,800

Divide the amount left by the weight of each crate:

13,800 / 70 = 197.14

They can load 197 crates.

6 0

3 years ago

In Which Quadrant is this true

34kurt

Given:

$\sin \theta$

$\tan \theta$

To find:

The quadrant in which $\theta$ lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only $\sin\theta$ and $\csc\theta$ are positive.

In Quadrant III, only $\tan\theta$ and $\cot\theta$ are positive.

In Quadrant IV, only $\cos\theta$ and $\sec\theta$ are positive.

We have,

$\sin \theta$

$\tan \theta$

Here, $\sin\theta$ is negative and $\tan\theta$ is also negative. It is possible, if $\theta$ lies in the Quadrant IV.

Therefore, the correct option is D.

5 0

3 years ago

Factor completely, 9x4 -225y8

Furkat [3]

Step-by-step explanation:

$9x4 -225y8 \\ = 3 \times 3 \times x \times 2 \times 2 -3 \times 5 \times 3 \times 5 \times y \times 2 \times 2 \times 2$

4 0

3 years ago

a 32m tall building cast a shadow. the distance from the top of the building to the tip of the shadow is 35m. find the length of

icang [17]

The length of the shadow is 14.2 m

Right angle triangle:

Right angle triangle has one of its sides as 90 degrees.

The height of the building is the opposite side of the triangle.

The distance from the top of the building to the tip of the shadow is 35 m is the hypotenuse side.

The length of the shadow is the adjacent side of the triangle.

Therefore,

c² = a² + b²

b² = 35² - 32²

b² = 1225 - 1024

b² = 201

b = √201

b = 14.17

b = 14.2 m

Hence the length of the shadow is 14.2 m.

learn more about right triangle here:

brainly.com/question/4278699

#SPJ9

3 0

1 year ago