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3 years ago

The price of a new car was 12,500 it is reduced to 11,625 work out the percentage reduction

Mathematics

1 answer:

amm18123 years ago

3 0

Answer:

93%.

Step-by-step explanation:

% Decrease = Decrease ÷ Original Number × 100

Divde 11,625 by 12,500 and multiply the answer by 100.

11,625 ÷ 12,500 × 100 = 93

The percentage reduction is 93%.

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Simplify please (10 points)

Ludmilka [50]

Answer:

The answer is 4th point

Step-by-step explanation:

√5(10 - 4√2)

= (√5×10)-(√5×4√2)

= 10√5 - 4√10

7 0

4 years ago

Read 2 more answers

What is the nth term of quadratic sequence 4 7 12 19 28

Anni [7]

We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:

Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².

We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.

Now we find the difference between the actual terms of the sequence and the numbers we just found:

4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.

Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3

7 0

3 years ago

4. As shown in Figure 5.111 to the right if the

Juli2301 [7.4K]

Answer:

Area of the shaded part is 3.14 square unit.

Step-by-step explanation:

Area of the shaded part = Area of large semicircle - (Area of two small semi circles)

Area of large semicircle with center O = $\frac{1}{2}(\pi r^2)$

= $\frac{1}{2}\pi (2)^{2}$

= 2π

Area of semicircle with center O' = $\frac{1}{2}\pi (1)^2$

= $\frac{\pi }{2}$

Area of semicircle with center O" = $\frac{\pi }{2}$

Now substitute these values in the formula,

Area of shaded part = $2\pi - (\frac{\pi }{2}+\frac{\pi }{2})$

= $\pi$

= 3.14 square unit

Area of the shaded part is 3.14 square unit.

7 0

3 years ago

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).