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3 years ago

Look at the diagram

Mathematics

1 answer:

creativ13 [48]3 years ago

8 0

Answer:

Step-by-step explanation:

18×(18+14) = x × (x + 0)

"+ 0" because it is a tangent at that point, there is no more line left going through the circle.

576 = x²

x = 24

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Helppppppppppppppppppppp

LenaWriter [7]

Answer:

5/8 = 0.625 and 62.5%

11/12 = 0.917 and 91.67%

1/4 = 0.25 and 25%

3/5 = 0.6 and 60%

Step-by-step explanation:

3 0

3 years ago

A television network, Network A, is scheduling its fall lineup of shows. For the Tuesday night 8 p.m. slot, Network A has sel

Mazyrski [523]

Answer:

The number of viewers Network A expects will watch their show is 1.4 million viewers.

Step-by-step explanation:

The expected value is calculated by multiplying the possible outcomes by the probability of their occurrence and adding the results

Therefore, we have the expected value given by the following expression;

Estimated network A viewers where network B schedule top show = 1.1 million viewers

Estimated network A viewers where network B schedule a different show = 1.6 million viewers

Probability that Network B will air its top show = 0.4

Probability that Network B will air another show = 0.6

We therefore have;

Expected value, E of Network A viewers is therefore;

E = 1.1 × 0.4 + 1.6 × 0.6 = 0.44 + 0.96 = 1.4 million viewers.

Network A expects 1.4 million viewers will watch their show.

3 0

3 years ago

g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa

adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is $\sigma = 0.0133$

Step-by-step explanation:

From the question we are told that

The upper specification is $USL = 1.68 \ mm$

The lower specification is $LSL = 1.52 \ mm$

The sample mean is $\mu = 1.6 \ mm$

The standard deviation is $\sigma = 0.03 \ mm$

Generally the capability index in mathematically represented as

$Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]$

Now what min means is that the value of CPk is the minimum between the value is the bracket

substituting value given in the question

$Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]$

=> $Cpk = min[ 0.88 , 0.88 ]$

$Cpk = 0.88$

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2

Now let assuming that

$\frac{\mu - LSL }{ 3 * \sigma } = 2$

$\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2$

=> $0.08 = 6 \sigma$

=> $\sigma = 0.0133$

$\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }$

=> $2$

Hence

$Cpk = min[ 2, 2 ]$

$Cpk = 2$

So $\sigma = 0.0133$ is the value of standard deviation required

3 0

3 years ago

Which technique is most appropriate to use to solve each equation? Drag the name of the technique into the box to match each equ

faltersainse [42]

(x + 3) (x + 2) = 0
To solve it, the most appropriate technique is:
1.) zero product property
The solutions are:
(x + 3) = 0
x = -3
(x + 2) = 0
x = -2

x² + 6 = 31
To solve it, the most appropriate technique is:
2.) square root property
x² = 31-6
x² = 25
x = +/- root (25)
x = +/- 5
The solutions are:
x = 5
x = -5

5 0

3 years ago

Read 2 more answers

If 8 cakes cost £4.00 how much would 3 cakes cost?

zzz [600]

Hello!

To calculate how much 3 cakes would cost, we must first find the cost of each individual cake.

To do this, we must divide the cost of 8 cakes by 8 cakes.

4.00 ÷ 8 = 0.5

This means that each individual cake costs $0.50. Multiply this by 3 to find the cost of 3 cakes.

0.50 × 3 = 1.50

Therefore, 3 cakes would cost $1.50.

4 0

3 years ago

Read 2 more answers