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tamaranim1 [39]
4 years ago
7

A large rectangle has length a + b and width c + d. Therefore, its area is (a + b)(c + d).

Mathematics
1 answer:
melamori03 [73]4 years ago
6 0

Answer:

The area of four small rectangles are ac, bc, ad and bd.

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2x 26<br> Please I need help I am failing math !!
almond37 [142]

Answer:

2*26=52

Step-by-step explanation: you can just use a calculator to find 2*26 and you will find that the answer to your question is 52.

3 0
4 years ago
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What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
For what value of x does 5^x-2 not equal zero?
frutty [35]

Answer:

E: all real numbers

Step-by-step explanation:

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3 years ago
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Robyn ran 5 3/4 miles last week. She ran 4 1/10 miles this week. How many more miles did she run last week?
padilas [110]
5 \frac{3}{4} -4 \frac{1}{10} &#10;
5 \frac{15}{20} -4 \frac{2}{20}
1 \frac{13}{20}
7 0
3 years ago
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Hellppp I needs it :((
solniwko [45]
The answer is 10 ft

4 0
3 years ago
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