I think the answer is the first one f(2) = g(2) and f(0) = g(0)
The answer is 11.25 mm.
A diameter of a circle is twice of its radius: d = 2r ⇒ r = d/2
small circle large circle
radius: r1 radius: r2 = ?
diameter: d1 = 15 mm
⇒ r1 = d1/2 = 15/2 mm
Since t<span>he ratio of the radii of two circles is 2:3, we have:
r1 : r2 = 2 : 3
which can also be expressed as:
</span>

<span>
We know that r1 is 7.5, so let's implement it:
</span>

Let's multiply both sides of the by 3r2:

⇒

⇒
<u>Question 1</u>
If we let
, then
.
Also, as
bisects
, this means
.
Thus, by the intersecting chords theorem,

However, as distance must be positive, we only consider the positive case, meaning FE=9
<u>Question 2</u>
If we let CE=x, then because AB bisects CD, CE=ED=x.
We also know that since FB=17, the radius of the circle is 17. So, this means that the diameter is 34, and as AE=2, thus means EB=32.
By the intersecting chords theorem,

However, as distance must be positive, we only consider the positive case, meaning CE=8
Answer:
Wdym is there any attachment ?
Step-by-step explanation: