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netineya [11]
3 years ago
14

Evaluate 7+q(r−8)2 when q = 3 and r = 10.

Mathematics
2 answers:
liberstina [14]3 years ago
8 0

<u>Answer:</u>

  • The solution of the expression is 19.

<u>Step-by-step explanation:</u>

<u>Given:</u>

  • q = 3
  • r = 10

<u>Work:</u>

  • => 7 + q(r − 8)2
  • => 7 + 3(10 - 8)2
  • => 7 + 6(10 - 8)
  • => 7 + 6(2)
  • => 7 + 12
  • => 19

Hence, <u>the solution of the expression is 19.</u>

Hoped this helped.

BrainiacUser1357

Citrus2011 [14]3 years ago
8 0

Answer:

19

Step-by-step explanation:

7 + q (r − 8) 2

7 + q (10 - 8) 2

7 + q * 2  * 2

7 + 3 * 2 * 2

7 + 6 * 2

7 + 12

19

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4 years ago
Which table represents a direct variation? Table A x 4 6 8 10 y 7 9 11 13 Table B x 4 6 8 10 y 12 18 24 30 Table C x 4 6 8 10 y
Greeley [361]

Answer:

We conclude that 'Table B' represents a direct variation.

Step-by-step explanation:

We know that when y varies directly with x, the equation is

y ∝ x

y = kx

k = y/x

where 'k' is called the constant of proportionality.

Table A

x     4 6 8 10

y     7 9 11 13

Finding k for all the pairs of x and y

k = y/x

k = 7/4, k = 9/6 = 3/2, k = 11 / 8, k = 13/11

As constant of proportionality 'k' does not remain constant.

Hence, table A does not represent a direct variation

Table B

x     4   6   8   10

y     12 18 24 30

Finding k all the pairs of x and y

k = y/x

k = 12/4 = 3, k = 18/6 = 3, k = 24/8 = 3, k = 30/10 = 3

As the constant of proportionality remains constant.

Therefore, the value of k = 3 for all the points in the table.

Hence, table B represents a direct variation.

Table C

x     4   6   8   10

y     1    3    5    7

Finding k all the pairs of x and y

k = y/x

k = 1/4, k = 3/6 = 1/2, k = 5/8, k = 7/10

As the constant of proportionality 'k' does not remain constant.

Hence, table C does not represent a direct variation.

Table D

x     4   6   8   10

y     3   3   3    3

Finding k all the pairs of x and y

k = y/x

k = 3/4, k = 3/6, k = 3/8, k = 3/10

As the constant of proportionality 'k' does not remain constant.

Hence, table D does not a direct variation.

Therefore, we conclude that 'Table B' represents a direct variation.

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Sarah has a collection of nickels, dimes, and quarters worth $28.75. She has 10 more dimes than nickels and twice as many quarte
Ymorist [56]

Answer:

Step-by-step explanation:

Write an equation for each statement:

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"Sarah has a collection of nickels, dimes, and quarters worth $15.75."

.05n + .1d + .25q = 15.75

:

"She has 10 more dimes than nickels"

d = n + 10

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"twice as many quarters as dimes."

q = 2d

:

How many coins of each kind does she have?

:

Take the 2nd equation and arrange it so n is in terms of d also

n + 10 = d

n = (d - 10)

:

In the 1st equation substitute (d-10) for n and 2d for q:

.05n + .1d + .25q = 15.75

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.05(d-10) + .1d + .25(2d) = 15.75

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.05d - .5 + .1d + .5d = 15.75

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.65d - .5 = 15.75

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.65d = 15.75 + .5

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.65d = 16.25

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d = 16.25/.65

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d = 25 dimes

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Remember the statement "twice as many quarters as dimes."

q = 2(25)

q = 50 quarters

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The statement "She has 10 more dimes than nickels"

n = 25 - 10

n - 15 nickels

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Check our solutions

.05(15) + .1(25) + .25(50) =

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