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2 years ago

Evaluate 7+q(r−8)2 when q = 3 and r = 10.

Mathematics

2 answers:

liberstina [14]2 years ago

8 0

Answer:

The solution of the expression is 19.

Step-by-step explanation:

Given:

q = 3
r = 10

Work:

=> 7 + q(r − 8)2
=> 7 + 3(10 - 8)2
=> 7 + 6(10 - 8)
=> 7 + 6(2)
=> 7 + 12
=> 19

Hence, the solution of the expression is 19.

Hoped this helped.

$BrainiacUser1357$

Citrus2011 [14]2 years ago

8 0

Answer:

Step-by-step explanation:

7 + q (r − 8) 2

7 + q (10 - 8) 2

7 + q * 2 * 2

7 + 3 * 2 * 2

7 + 6 * 2

7 + 12

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What is the simplified form of 12x/900x²y4z6?

zalisa [80]

Answer:

$360xy^2|xz^3|$

Step-by-step explanation:

Given expression:

$12x \sqrt{900x^2y^4z^6}$

$\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:$

$\implies 12x \sqrt{900}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

Replace 900 with 30² :

$\implies 12x \sqrt{30^2}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

$\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:$

$\implies 12x \cdot 30|x|\sqrt{y^4}\sqrt{z^6}$

$\implies 360x|x|\sqrt{y^4}\sqrt{z^6}$

(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).

$\textsf{Apply exponent rule} \quad \sqrt{a^m}=a^{\frac{m}{2}}:$

$\implies 360x|x|\cdot y^{\frac{4}{2}}\cdot z^{\frac{6}{2}}$

Simplify:

$\implies 360xy^2|xz^3|$

(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).

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1 year ago

What is the value of the expression (9+15)*3+2

dimulka [17.4K]

First do parenthesis the multiplication then add
9+15=24*3=72+2=74 :)hope this helps

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2 years ago

Find the pay earned: 33 hours at $5.15 per hour

Inessa [10]

$169.95

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3 years ago

Read 2 more answers

20. A ball is dropped from a height of a little over 5 feet, and the height is measured at small intervals. The table below show

nekit [7.7K]

Step 1:

a) Write the quadratic model

a = -15.64

b = -1.24

c = 5.23

$P(t)=-15.64t^2\text{ - 1.24t + 5.2}3$

b) t = 0.30

$\begin{gathered} P(t)=-15.64t^2\text{ - 1.24t + 5.2}3 \\ =\text{ -15.64 }\times0.3^2\text{ - 1.24}\times\text{ 0.3 + 5.2}3 \\ =\text{ -1.4076 - 0.372 + }5.23 \\ =\text{ 3.45} \end{gathered}$

c) t = 0.52 seconds

$\begin{gathered} p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ =\text{ -15.64}\times0.52^2\text{ - 1.23}\times0.52\text{ + 5.23} \\ =\text{ -4.23 - 0.64 + 5.23} \\ =\text{ 0.36} \end{gathered}$

d) 0.30 is more likely to be relaible.

$\begin{gathered} p(t)\text{ = 1} \\ p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ 1=-15.64t^2\text{ - 1.23t + 5.23} \\ -15.64t^2\text{ - 1.23t + 4.23 = 0} \\ t\text{ = 0.48222} \\ \text{t = 0.48 seconds} \end{gathered}$

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1 year ago

I need help with these two problems

erastova [34]

Number 5 is 15.9 kilograms

And number 6 is 6 million cubic feet per minute

You just cross multiply

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3 years ago