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deff fn [24]
3 years ago
9

!PLEASE HELP ME THIS IS 10 POINTS!

Mathematics
2 answers:
ruslelena [56]3 years ago
7 0

Answer:

a i think

Step-by-step explanation:

im not good at math

Finger [1]3 years ago
5 0

Answer:

The answer is C. 42 and 62

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Write this polynomial in standard form- (5a+2)(a+4)
ikadub [295]

Answer:

5a²+22a+8

Step-by-step explanation:

(5a+2)(a+4)

5a² + 20a + 2a + 8

5a² + 22a + 8

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3 years ago
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Can someone give me a simple answer to this problem
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3 years ago
How many time does 8 go into 448​
Andrej [43]

Answer: 56 times

Step-by-step explanation:

7 0
1 year ago
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Abby went to the store to buy ice cream for her party. Each box costs $3. She has a coupon for 20% off her total. If Abby buys 3
ollegr [7]

Answer: 7.2$

hope it helps :)

step-by-step explanation:

Cost of each box = 3$

Cost of 3 boxes without 20% coupon = 9$

With 20% off Coupon = 9 by 100 multiplied by 20

                                     (the zero's cut with each other leaving)

                                     = 9 by 10 multiplied by 2

                                     (9 multiplied by 2 = 18)

                                     = 18 by 10

                                     (18 divided by 10 = 1.8)

                                     = the 20% of 9$ is equal to 1.8

                                        when subtracted with the total cost leaves 7.2$

4 0
3 years ago
Which expression is equivalent to sqrt8x^7y^8? assume x>0
Ilia_Sergeevich [38]

Answer:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

Step-by-step explanation:

Given

\sqrt{8x^7y^8

Required

Evaluate

\sqrt{8x^7y^8

Separate each factor with multiplication sign

\sqrt{8*x^7*y^8

Express 8 as 4 * 2 and x^7 as x^6 * x

\sqrt{4 * 2 *x^6 * x*y^8

Split each factor

\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Evaluate \sqrt4

2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Apply law of indices:

2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}

2 * \sqrt{2} * x^3 * \sqrt{x} * y^4

Reorder

2* x^3 * y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2*x}

2x^3y^4 * \sqrt{2x}

2x^3y^4 \sqrt {2x

Hence:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

8 0
3 years ago
Read 2 more answers
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