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3 years ago

Find the value of x in simplest radical form

Mathematics

1 answer:

Dominik [7]3 years ago

4 0

Answer:

Step-by-step explanation:

h^2=x^2+y^2, here x and y are equal so we can say

h^2=2x^2, we see that h=2(2^(1/2)) so

2x^2=8

x^2=4

x=2

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Need help with some practice questions since all are different types I'm asking alot sorry!

sasho [114]

Answer:

Yes

Step-by-step explanation:

If they're perpendicular, that means that angle ECM = 90 degrees and angle ACE = 90 degrees. To figure out if this works, plug that into the two equations they give:

ECM = 3x + 15

becomes

90 = 3x + 15

75 = 3x

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ACE = 4x - 10

becomes

90 = 4x - 10

100 = 4x

25 = x

Since you get x = 25 for both, you know that they are perpendicular because they both measure 90 degrees

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3 years ago

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sleet_krkn [62]

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3 years ago

In the xy -coordinate plane, the coordinates of point s are (-2,-6), and coordinates of point T are (18,9). Point Q lies on line

ira [324]

Answer:

(6,0)

Step-by-step explanation:

The coordinates of the points dividing the line segment in ratio m:n can be calculated as:

$(\frac{mx_{2}+nx_{1}}{m+n} ,\frac{my_{2}+ny_{1}}{m+n} )$

Here x1, y1 are the coordinates of first point S (-2, -6) and x2, y2 are the coordinates of second point T(18, 9).

In this case m will be 2 and n will be 3 as the ratio is 2:3

Using all these values we can find the coordinates of point Q

$( \frac{2(18)+3(-2)}{2+3},\frac{2(9)+3(-6)}{2+3} )\\\\ = (\frac{30}{5} ,\frac{0}{5} )\\\\ =(6,0)$

Thus, the coordinates of point Q which divides the line segment ST in ratio of 2:3 are (6,0)

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Tpy6a [65]

Answer:

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