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VLD [36.1K]
4 years ago
11

Given A={1,2,3}, B={2,4,6} and C={1,2,3,4,5,6}, then A ∩ (B ∩ C) =

Mathematics
1 answer:
oksian1 [2.3K]4 years ago
4 0

Answer:

Step-by-step explanation:

A={1,2,3}

B={2,4,6}

C={1,2,3,4,5,6}

B∩C={2,4,6}

A∩(B∩C)={1,2,3}∩{2,4,6}={2}

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Answer:

Step-by-step explanation: From the above question, we have been given some hints to assist in the number interpretation.

Answers are:

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3.25E4

1.56e-9

The above selected numbers have been selected using the hints below:

You cannot have commas in numbers.

You cannot have a space in a number.

You cannot substitute the letter O for zero or the letter l for 1.

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rashid saves $150 each month. he wants to know how much he will have saved in 2 years. he writes the rule s=m+150 to help him fi
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3 years ago
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ikadub [295]
You are the correct one. If the person is not able to proof, and if you are rather sure about your answer, it is better to take your own answer instead :)

-9d = 63
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4 years ago
Help please with steps
SOVA2 [1]

From the image, we can see the amount of water in Liters are in the beaker.

The beaker is marked with numbers that are skip counting by 10. (10,20,30) so on. There are 4 ticks below the 10, 5 if you count the 10.

So that means 10/5 = 2 L per tick.

The water goes above the 30 mark and under the 40 mark, which means it's somewhere in the 30's.

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One of the wagers in roulette is to bet that the ball will stop on a number that is a multiple of 3. (Both 0 and 00 are not incl
goldenfox [79]

Answer:

The player's expectation is a loss of 20 cents.

Step-by-step explanation:

In a game of roulette, there are 38 slots where the ball can stop.

The slots are numbered as follows: {0, 00, 1, 2, 3 ..., 36}.

So, N = 38.

The slots which are multiples of 3 are:

S = {3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33 and 36}

So, n (S) = 12.

Let <em>X</em> = the ball stops on a number that is a multiple of 3

The probability that the ball stops on a number that is a multiple of 3 is:

P(X)=\frac{n (S)}{N}=\frac{12}{38}=0.32

It s provided that the player wins double the amount bet if the ball stops on a number that is a multiple of 3.

Compute the player's expectation as follows:

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Thus, the player's expectation is a loss of 20 cents.

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