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2 years ago

5

Points A(2,2) and B(7,14) are two vertices of an equilateral

1 answer:

Dvinal [7]2 years ago

7 0

Answer:

poi nts

Step-by-step explanation:

7

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Which table of values will generate this graph?

IRINA_888 [86]

Answer:

Step-by-step explanation:

3

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3 years ago

Hi I'm looking to solve this question for my work but I'm super stuck and I need help asap. Thsnks

MrMuchimi

10w + 9 Are you combing like terms?

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2 years ago

What is the answer i need answers now

ad-work [718]

The answer is 10/3. Because you have 3 wholes and 1/3 so, 3x3 is 9 and you still have the extra 1 so 9+1=10 therefore your answer would be 10/3

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1 year ago

Read 2 more answers

(3+7i)+(-5+2i)-(-7+6i)

anzhelika [568]

I believe that the answer to your question is 5 + 3 i?

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3 years ago

Evaluate the function at the indicated values if possible. If an indicated value is not in the domain, say so.

goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

$f(x)=\frac{x+7}{x^2-9}$ is the given function.

We are asked to find:

$f(-7)$

$f(2)$

$f(3)$ .

f(-7) means to replace x in the expression called f with -7:

Evaluate $\frac{x+7}{x^2-9}$ at $x=-7$

$\frac{(-7)+7}{(-7)^2-9}$

$\frac{0}{49-9}$

$\frac{0}{40}$

$0$

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate $\frac{x+7}{x^2-9}$ at $x=2$

$\frac{2+7}{2^2-9}$

$\frac{9}{4-9}$

$\frac{9}{-5}$

$\frac{-9}{5}$

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate $\frac{x+7}{x^2-9}$ at $x=3$

$\frac{3+7}{3^2-9}$

$\frac{10}{9-9}$

$\frac{10}{0}$

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0

3 years ago