Answer:
Step-by-step explanation:
<u>Vertical Throw</u>
It refers to a situation where an object is thrown verticaly upwards with some inicial speed v_o and let in free air (no friction) until it completes its movement up and finally returns to the very same point of lauch. The only acting force is gravity
The projectile formula is given as
where t is time in seconds, h is the height in feet and v is the speed in ft/sec
We are required to find the time t where h=120 ft, knowing 
Rearranging
This is a second-degree equation which will be solved with the formula
Two solutions are obtained
Both solutions are possible because the ball actually is at 120 ft in its way up and then when going down
The radius of a circle is half of the diameter
10.) (6/5)= 1.2
1.2/2=.6
The radius of the circle in question 10 is .6 or 1/2 inch
11.) because x (diameter) is not defined in this problem. We can't solve directly for x, but we know the radius is half of the diameter
so we can say
r= 1/2x
9/27 is equivalent to 2/27
Answer:
309 feet
Step-by-step explanation:
given that the height can be represented by a quadratic equation, we can say that the general form of the equation will look something like this:
h(x) = Ax² + Bx + C
we know that at the starting point of the launch that time = 0 (i.e x = 0) and hence h (x) = 0, if we substitute this into our equation, we can find the value for C
h(0) = A(0)² + B(0) + C = 0
C = 0
Hence the equation becomes
h(x) = Ax² + Bx
Given when x = 1, h(1) = 121,
121 = A(1)² + B(1)
A + B = 121 ------> eq 1
Given when x = 2, h(2) = 224,
224 = A(2)² + B(2)
4A + 2B = 224 (divide both sides by 2)
2A + B = 112------> eq 2
Solving the system of equations which comprise eq 1 and eq 2 using your favorite method, we end up with A = -9 and B = 130
our equation becomes:
h(x) = -9x² + 130x
when x = 3
h(3) = -9(3)² + 130(3) = 309 feet
