3∅ can be rewritten as (2∅+∅)
sin(3∅) = sin(2∅ + ∅<span>)
Opening brackets on the right hand side;
= sin2</span>∅ cos ∅ + cos2∅sin<span>∅
</span><span>This simplifies to;
= 2sin</span>∅cos^2∅ + sin∅ (1- 2sin^2∅<span>)
= sin</span>∅ (2cos^2∅ + 1 - 2sin^2∅<span>)
= sin</span>∅ (2(1 - sin^2∅) +1-2sin^2∅<span>)
= 3sin</span>∅ - 4sin^3<span>∅</span>
Step-by-step explanation:
<em>Hi</em><em>,</em>
<em>Let's</em><em> </em><em>describe</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>listing</em><em> </em><em>method</em><em>;</em>
<em>S</em><em>=</em><em> </em><em>{</em><em>8</em><em>,</em><em>1</em><em>6</em><em>,</em><em>2</em><em>4</em><em>}</em><em>.</em>
<em><u>Hope</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>got</u></em><em><u> </u></em><em><u>it</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Sin(angle) = opposite leg / hypotenuse (X)
sin(48) = 5 / X
X = 5 / sin(48)
X = 6.7
The answer is C.
Answer:
The required equation is 4h-6=70.
Step-by-step explanation:
It is given that Jahlil is 6 inches shorter than 4 times his sister’s height. Jahlil’s height is 70 inches.
Let h be his sister’s height in inches.
4 times of his sister’s height = 4h
6 inches shorter than 4 times his sister’s height = 4h - 7
Since Jahlil is 6 inches shorter than 4 times his sister’s height, therefore the Jahlil's height is
It is given that Jahlil’s height is 70 inches.
Therefore the required equation is 4h-6=70.
