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Gelneren [198K]
2 years ago
11

The coordinate plane shows the graphs of two exponen functions which equation is true?

Mathematics
1 answer:
ankoles [38]2 years ago
4 0

Answer:

A

Step-by-step explanation:

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Can someone help me with this thanks ​
Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}

\frac{BC}{sinA}=\frac{AB}{sinC}

\frac{2}{sin25}=\frac{3}{sinC}

\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

\frac{BC}{sinA}=\frac{AC}{SinB}

\frac{2}{sin25}=\frac{l}{sin(115.66)}

l=\frac{2\times sin(115.66)}{sin25}

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

brainly.com/question/25852087

#SPJ1

8 0
1 year ago
If the congruent angles of an isosceles triangle each measure 41 degrees, What is the measure of the third angle?
geniusboy [140]

Answer:

98 degrees

angles of a triangle always add up to 180 degrees. 41+41= 82. 180-82= 98

3 0
3 years ago
The figure shows a square, a regular pentagon and a regular hexagon put together. What is the measure of ∠BAC
Elan Coil [88]

Answer:

42

Step-by-step explanation:

One angle of a regular pentagon = 108°

One angle of a regular hexagon = 120°.

One angle of a square = 90°

∴ ∠BAC = 360 – (108 + 20 + 90) 360 – 318 = 42°

8 0
1 year ago
Which of the following best describes (x + 6)(x – 6)
FromTheMoon [43]

1) take x*x

2) x*-6

3)6*x

4)6*-6

answer x^2-36

5 0
3 years ago
Read 2 more answers
Find x, if the distance end points is (x,1) and (4,4) with the total distance is the square root of 10.
Alex Ar [27]
Okay, take a look at diagram 1 (I know it's rubbish I did it on paint :D), this shows all the information you've given in the question. The two coordinates and the distance between them.

Now if we draw additional lines on this diagram, we can make a right-angled triangle (this is on diagram 2). We can also work out the lengths of the additional sides because we know both coordinates at the end-points of the additional lines.

Finally because this is a right-angled triangle, Pythagoras' theorem must apply to its sides meaning
( \sqrt{10} )^2 = (x-4)^2 + 3^2
10 = (x-4)^2 + 9
(x-4)^2 = 1 \Rightarrow x-4 = 1
therefore x=5.

3 0
2 years ago
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