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rewona [7]
3 years ago
5

Please answer any one them thank you so much

Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Answer:

left to right:

4a + 12

6a - 36

12c+6

10d + 30

40e + 64

48f - 72

14g - 20

66h - 36

22 + 14i

90j - 27

27k - 30

65m - 143

Step-by-step explanation:

I really hope this helped

Sunny_sXe [5.5K]3 years ago
5 0

Answer:

is this alegebra? if so im failing in it.

Step-by-step explanation:

because im bad at alegebra

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Nadusha1986 [10]
x^2+7x=-12\\x^2+7x+12=0\\x^2+3x+4x+12=0\\x(x+3)+4(x+3)=0\\(x+4)(x+3)=0\\x=-4\ and \ x=-3
5 0
3 years ago
What is the value of x that makes the statement true?<br><br> 12x + 16 = 50x - 3<br><br> x =
kvasek [131]

Answer:

  • x = 1/2

Step-by-step explanation:

Given

  • 12x + 16 = 50x - 3

Solving for x

  • 12x + 16 = 50x - 3
  • 50x - 12x = 16 + 3
  • 38x = 19
  • x = 19/38
  • x = 1/2
6 0
3 years ago
Let the (x; y) coordinates represent locations on the ground. The height h of
grigory [225]

The critical points of <em>h(x,y)</em> occur wherever its partial derivatives h_x and h_y vanish simultaneously. We have

h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5

Substitute <em>y</em> in the second equation and solve for <em>x</em>, then for <em>y</em> :

2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}

This is to say there are two critical points,

(x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)

To classify these critical points, we carry out the second partial derivative test. <em>h(x,y)</em> has Hessian

H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}

whose determinant is 192y-16. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and h_{xx} are positive at the point, then it's a local minimum

• if the determinant is positive and h_{xx} is negative, then it's a local maximum

• otherwise the test fails

We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

while

\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0

So, we end up with

h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}

7 0
3 years ago
In a certain large state university, older students get to choose their classes before younger students; that often means that f
lord [1]

There is a good evidence that freshmen have a better than 32% chance of getting the course if they ask for it.

The null hypothesis is that  freshmen do not have a better than 32% chance of getting the course if they ask for it.

The alternative hypothesis is freshmen have a better than 32% chance of getting the course if they ask for it.

<h3>What are the chance that a freshman would get the course?</h3>

The chance of getting the course = number of freshmen who got the course / total number of freshmen

73 / 200 = 36.50%

<h3>What are the null and alternative hypothesis?</h3>

The null hypothesis states that there is no relationship between the population parameters. It is known as the true hypothesis. In the question, the population parameters are freshmen and getting the course

The alternative hypothesis states that there is a relationship between the population parameters.

To learn more about the null hypothesis, please check: brainly.com/question/4454077

#SPJ1

7 0
2 years ago
Please help! Desperate. Will give brainiest
alisha [4.7K]
I think s NO 4 i hope that was help.
4 0
4 years ago
Read 2 more answers
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