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Dafna11 [192]
3 years ago
13

A student has passed 60 percent of the 20 quizzes he has written so far successfully. If the student writes 50 quizzes during th

e year, and passes 80 percent of the remaining quizzes successfully, what is the percent of all successful quizzes for the entire year?
Mathematics
2 answers:
Otrada [13]3 years ago
6 0

Answer:

72%

Step-by-step explanation:

calculate the quizzes passed for the first 20 quizzes

quizzes first passed = 60% of first 20 quizzes

= (60/100) x 20 = 12 quizzes

now calculate the quizzes passed for the remaining 30 quizzes (50-20 = 30)

quizzes passed later = 80% of next 30 quizzes

= (80/100) x 30 = 24 quizzes

therefore total quizzes passed = 12 +24 = 36 quizzes

percentage of quizzes passed =(total no of quizzes passed / total quizzes written) x 100

percentage of quizzes passed = (36/50) x 100 = 72%

mart [117]3 years ago
4 0

Answer:

72%

Step-by-step explanation:

Start by turning both percentages into decimals.  To do this take the percent and divide it by 100.  So, 60% = 60/100 or .6 and 80% = 80/100 or .8.

Next the student has already completed 20 quizzes.  So, 50-20=30 remaining quizzes.

Quizzes already taken:

.6*20

= 12 passed quizzes.

The remaining quizzes for the school year:

.8*30

= 24 quizzes

So, Finally add them both together and divide by the total amount of quizzes:

12+24

= 36 passed quizzes

36/50

=.72

Now to convert it back into a fraction you multiply the decimal by 100.

.72*100

= 72%

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What is the rule in the input/output table? A) add 4 B) subtract 4 C) divide by 2 D) multiply by 2 | inputs | 4 6 and 8 | output
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A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selec
natali 33 [55]

Answer:

0.3968 = 39.68% probability this shipment passes inspection.

Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

50 parts means that N = 50

4 defective means that k = 4

10 are chosen, which means that n = 10

What is the probability this shipment passes inspection?

Probability that none is defective, so:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968

0.3968 = 39.68% probability this shipment passes inspection.

6 0
3 years ago
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