Hello,
Let n-2,n-1,n,n+1 the foru numbers
s=n-2+n-1+n+n+1=4n-2
95<=4n-2<=105
==>97<=7n<=107
==>24.25<=n<=26.75
==>25<=n<=26
if n=25 s=98
if n=26 s=102
nah buddy
Step-by-step explanation:
Answer:
-sqrt(3) -i = 2 cis (7pi/6)
Step-by-step explanation:
-sqrt(3) -i
We can find the radius
r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)
= sqrt( 3 + 1)
= sqrt(4)
= 2
theta = arctan (y/x)
arctan (-1/-sqrt(3))
arctan (1/sqrt(3))
theta = pi/6
But this is in the first quadrant, and we need it in the third quadrant
Add pi to move it to the third quadrant
theta = pi/6 + 6pi/6
=7pi/6
-sqrt(3) -i = 2 cis (7pi/6)
3 is common and therefore the factorization of the expression will be
3(w-2)
Answer: 2x(3+4)
Step-by-step explanation: 2x represents the one scoop of food twice a day, and 3+4 represents her 3 cats and 4 dogs.
