I BELIEVE that there are 22 quarters, 13 dimes, and 7 nickels I’m super super sorry if wrong
Let event A = Caroline buys fruit, event B = Caroline buys CD, Ac and Bc are complementary events.
Events AB, ABc, AcB and AcBc are jointly exhaustive and disjoint, hence P(AB) + P(ABc) + P(AcB) +P(AcBc) =1.
Events A and B independent, hence Ac and Bc independent too and probability P(AcBc) = P(Ac)*P(Bc) = (1 - P(A))(1-P(B)) = 0.6*0.4 = 0.24.
Required probability P(AB + ABc + AcB ) = P(AB) + P(ABc) + P(AcB) = 1- P(AcBc) = 1 - 0.24 = 0.76.
Answer: Probability that Caroline buys fruit, a CD or both is 0.76.
Answer: 6) 15 1/10
Step-by-step explanation:
Add the whole numbers and then find a common number for the bottom fraction. So that'd be ten. To get to ten from 2 you'd multiply by five then multiply the top number by five too. That gets you 5/10 and do the same for the other fraction. Get the bottom number to ten then whatever you multiply by do the same to the top. After doing that putting the fractions together which gets you 11/10. That'd make 1 1/10 so that makes it 15 instead of 14 whole
Answer:
PLEASE GIVE BRAINLIST
each total= 103.68
but if you're talking about divided in into the amount of tacos will be:
2.43 each
HOPE THIS HELPED
Answer:
possibly you could use kid per candy, number of trickery treaters or something
you could explain lets say over the holidays Miss. So and So's class's kids got an average of around 4-6 Christmas presents while Miss. Mary Sue's class had kids with 2 presents and kids with 12, since the range between 2-12 is bigger it had a greater standard of deviation
(hopefully this helps and I am not overcomplicating or incorrecting the standard of deviation, good luck)