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DIA [1.3K]
2 years ago
15

Find x on this triangle

Mathematics
1 answer:
blsea [12.9K]2 years ago
7 0

Answer:

3 sqrt(3) =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj / hyp

cos 30 = x/6

6 cos 30 = x

6 ( sqrt(3)/2) = x

3 sqrt(3) =x

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The graph below shows three functions: Graph of function f of x equals 0.5 to the power x. Graph of function g of x is a line se
Phantasy [73]

Answer:   f(x)= 0.5^x has all real value as its domain.

Explanation: since, we have three functions f(x)=0.5^x,

while g(x) and p(x) are line segments.

Now, g(x) is a function by a line segment which passes through two points (-1.8,-3) and ( 1,3.8).

Thus it is clear that its domain will be the ends points. so domain of the function g(x) will be [-1.8, 3.8] which is the subset of real numbers set (R).

Similarly, domain of function p(x) will be [1.7, 1], which is also the subset of R.

But, when we talk about f(x) it contains all the possible value of x. Thus we can say that f(x)= 0.5^x has R as its domain.

8 0
3 years ago
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How do I solve <br> This I need help
Delvig [45]
So we have:

xk = v + w           solve for x
divide both sides by k to isolate the variable x:

x = (v+w)/k

^^This is your answer!

Hope I helped!
6 0
2 years ago
Choose the product. a 3 b 2 · 4ab 3 <br><br> 4a3b5<br><br> 4a3b6<br><br> 4a4b5
zvonat [6]
A³ b² 4ab³

Rearrange order:

4  a³ a  b² b³

Now add up the exponents from same base:

4  a³⁺¹  b²⁺³

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Final answer: 4 a⁴ b⁵
5 0
3 years ago
How many 16ths are there in 1 inch?
laiz [17]

Answer: There are \frac{1}{16} in one inch.

7 0
3 years ago
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I need help asap please
Anna [14]

Answer:

-3 or decreasing by 3

Step-by-step explanation:

To find the average change, you only care about the first and last point which would be (3,17) and (8,2)

the overall change during that time is 2-17=-15 (for the f(x) side )

the overall change during that time is 8-3=5(for the x side)

all we have to do is -15/5=-3

therefore the average rate of change is -3

5 0
2 years ago
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