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3 years ago

51

Mathematics

1 answer:

Fiesta28 [93]3 years ago

3 0

Answer:

let inverse f(x) be m:

$m = \frac{1}{2x + 1} \\ 2x + 1 = \frac{1}{m} \\ 2x = \frac{1 - m}{m} \\ x = \frac{1 - m}{2m}$

substitute x in place of m:

${ \bf{ {f}^{ - 1}(x) = \frac{1 - x}{2x } }}$

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