The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
5
Step-by-step explanation:
This means that 9/(2x-1)=15/(3x), so 27x=30x-15. This means that 3x=15, so x=5.
Answer:
7
Step-by-step explanation:
how many fives are in 35? thats the answer
<span>The answer is 20 feet by 20 feet. Let's solve the equation: (x – 8)^2 = 144. (x - 8)^2 = 12^2. Since a^2 = b^2 is the same as a = b, then (x - 8)^2 = 12^2 can be simplified to: x - 8 = 12. Now, solve for x. x = 8 + 12. x = 20. Therefore, the dimensions of the original lawn were 20 feet by 20 feet.</span>
