All categories

3 years ago

Here is a graph of a quadratic function f(x). What is the minimum value (y-value only) of f(x)?

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

4 0

Answer:

Zero.

Step-by-step explanation:

The minimum value is where the function touches the x axis , at y = 0.

You might be interested in

Simplify -5^5 ÷ -5^-6

Tpy6a [65]

Answer:

5^11

Step-by-step explanation:

-5^5 ÷ -5^-6

5^5 divide 5^-6

5^11

5 0

3 years ago

A. 0.1925 B.0.1575 C.0.2925 D.0.3575 HELP PLEASE!!!

Elena-2011 [213]

A, because:

Hardcover: 0.35
Buys hard cover and non-fiction: 0.35 x 0.55 = 0.1925

3 0

4 years ago

(I|HEEEEELP)At the city museum, child admission is

lapo4ka [179]

LIKE 15.SOMETHING IDK M8 SORRY

5 0

4 years ago

3/5 of those attending a picnic decided to play touch football. one more decided to play, there were 16 players. how many attend

Effectus [21]

The answer is 9.6
3/5 of 16=9.6

7 0

3 years ago

P(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).

Mila [183]

Answer:

The polynomial is:

$p(x) = -x^3 - 2x^2 + 5x + 6$

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that $x_1 = -3, x_2 = -1, x_3 = 2$ . Thus

$p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)$

$p(x) = a(x - (-3))*(x - (-1))*(x-2)$

$p(x) = a(x+3)(x+1)(x-2)$

$p(x) = a(x^2+4x+3)(x-2)$

$p(x) = a(x^3+2x^2-5x-6)$

Passes through the point (1,12).

This means that when $x = 1, p(x) = 12$ . We use this to find a.

$12 = a(1 + 2 - 5 - 6)$

$-12a = 12$

$a = -\frac{12}{12}$

$a = -1$

Thus

$p(x) = -(x^3+2x^2-5x-6)$

$p(x) = -x^3 - 2x^2 + 5x + 6$

6 0

3 years ago