2 years ago

Here is a graph of a quadratic function f(x). What is the minimum value (y-value only) of f(x)?

Mathematics

1 answer:

Lubov Fominskaja [6]2 years ago

4 0

Answer:

Zero.

Step-by-step explanation:

The minimum value is where the function touches the x axis , at y = 0.

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liraira [26]

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3 years ago

Which choice is equivalent to the quotient shown here when x is greater than or equal to 0?

Dima020 [189]

Answer: OPTION C

Step-by-step explanation:

Remember that:

$\sqrt[n]{a^n}=a$

And the Product of powers property establishes that:

$a^m*a^n=a^{(mn)}$

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$\frac{\sqrt{18x} }{\sqrt{32} }$

Descompose 18 and 32 into their prime factors:

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Substitute into the expression, then:

$\frac{\sqrt{(2*3^2)x} }{\sqrt{2^4*2} }$

Finally,simplifying, you get:

$\frac{3\sqrt{(2)x} }{2^2\sqrt{2} }=\frac{3\sqrt{2x}}{4\sqrt{2}}=\frac{(3)(\sqrt{x})(\sqrt{2})}{(4)(\sqrt{2})}= \frac{3\sqrt{x}}{4}$

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3 years ago

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GuDViN [60]

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2 years ago

I’m so confused on how to do this

dimaraw [331]

Answer:

Step-by-step explanation:

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3 years ago