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Paladinen [302]
3 years ago
8

3(2x – 14) = -3(-13 + x)

Mathematics
2 answers:
lana [24]3 years ago
8 0

Answer:

9

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Sergio039 [100]3 years ago
8 0

AnswerX=9

Step-by-step explanation:

6x-42=39-3x

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Answer:

The indicated probability of P(D \cup F')=\frac{25}{26}

Step-by-step explanation:

Probability of an event E to be;

P(E) = \frac{Number of events within E}{Total number of possible outcomes}

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Total number of possible outcomes =  52 cards.

Let the event be D and F as follows;

D : Drawn card is a black card

F : Drawn card is a 10 card.    

Then,

From the given condition:

P(D) = \frac{26}{52}   [Out of 52 cards, 26 were black] ,

P(F) = \frac{4}{52}    [Out of 52 cards, there are four  10 cards]

For any two events A and B we always have;

P(A \cup B) = P(A)+P(B)-P(A \cap B)

Now, we have to find the indicated probability:

P(D \cup F')=P(D)+P(F')-P(D \cap F')               ......[1]

First find the P(F');

P(F') =1-P(F) = 1-\frac{4}{52} =\frac{52-4}{52} =\frac{48}{52}

Also, to find P(D \cap F').

We use the formula :

For any event A and B independent variable.

P(A \cap B) =P(A) \cdot P(B)

then;

P(D \cap F') =P(D) \cdot P(F') = \frac{26}{52} \cdot \frac{48}{52} =\frac{24}{52}

Now, substitute these in [1];

P(D \cup F')=\frac{26}{52} +\frac{48}{52} -\frac{24}{52}=\frac{26+48-24}{52} =\frac{50}{52} = \frac{25}{26}

Therefore, the probability of P(D \cup F')=\frac{25}{26}



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