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Svet_ta [14]
3 years ago
15

Find the sum of 4(m+2)+3(6m−4)

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
It should be 22m -4



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What is the equation of the line that passes through the point (6, 3) and has a slope of -2?
tekilochka [14]

We know the equation of a line is y=mx+b. We know the slope (m) is -2 and all we need is the intercept (b).

Since we know one point, we can plug in 6 for x and 3 for y (along with -2 for m) in our equation and then solve for b.

3= -2*6 + b

3= -12 + b

15 = b

Since we now know the intercept we can now write our equation:

y= -2x + 15

3 0
3 years ago
Helpp lang pooo di ko alam eh..<br>A.P po subject
docker41 [41]

Answer:

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8 0
3 years ago
Determine whether or not the vector field is conservative. if it is, find a function f such that f = ∇f. if the vector field is
amm1812
\dfrac{\partial f}{\partial x}=3y^2z^3\implies f(x,y,z)=3xy^2z^3+g(y,z)

\dfrac{\partial f}{\partial y}=6xyz^3+\dfrac{\partial g}{\partial y}=6xyz^3
\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

\dfrac{\partial f}{\partial z}=9xy^2z^2+\dfrac{\mathrm dh}{\mathrm dz}=9xy^2z^2
\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C

\implies f(x,y,z)=3xy^2z^3+C

The potential function exists, so \mathbf f is indeed conservative.
7 0
4 years ago
PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!
Mashutka [201]

Answer:

5b^9/a^3

Step-by-step explanation:

3 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
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