24 ÷ 21 with out any remainders
2 answers:
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Answer:
<h2>In the attachment.</h2>Step-by-step explanation:
Put each value of x from the set {2, 3, 4, 5, 6}
to the equation y = 2|x - 4| + 3:
x = 2 → y = 2|2 - 4| + 3 = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (2, 7)
x = 3 → y = 2|3 - 4| + 3 = 2|-1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (3, 5)
x = 4 → y = 2|4 - 4| + 3 = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3 → (4, 3)
x = 5 → y = 2|5 - 4| + 3 = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (5, 5)
x = 6 → y = 2|6 - 4| + 3 = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (6, 7)
Mark the points in the coordinates system.
The domain is only five numbers, therefore the graph of this function is only five points.
now, let's expand the squared term to get the standard form of the quadratic.