Let us recall parallelogram properties, which states that opposite angles of parallelogram are congruent.
We can see from graph that side US is parallel to TR and measure of angle U equals to measure of angle R, therefore, quadrilateral drawn in our given graph is a parallelogram.
Since we know that opposite sides of parallelogram are congruent. In our parallelogram UT=SR and US=TR.
In our triangle STU and triangle TSR side TS=TS by reflexive property of congruence.
Therefore, our triangles are congruent by SSS congruence.
Answer:
f(-7) = 268
Step-by-step explanation:
f(x) = 4x^2 – 10x + 2
Let x = -7
f(-7) = 4(-7)^2 – 10(-7) + 2
Exponents first
f(-7) = 4(49) – 10(-7) + 2
Multiply
f(-7) = 196 + 70 + 2
f(-7) = 268
Answer:
Only the isosceles trapezoid has an area of 32 cm².
Step-by-step explanation:
Let's calculate the area of each polygon.
For the two triangles we have:

This polygon does not have an area of 32 cm².
For the rectangle we have:

This polygon does not have an area of 32 cm².
For the rectangle trapezoid we have:
So, this polygon does not have an area of 32 cm².
Finally, for the isosceles trapezoid:
This polygon does have an area of 32 cm².
Therefore, only the isosceles trapezoid has an area of 32 cm².
I hope it helps you!
Answer:
2
Step-by-step explanation:
Answer:
B: II, IV, I, III
Step-by-step explanation:
We believe the proof <em>statement — reason</em> pairs need to be ordered as shown below
Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC — given
Draw Line segment BE Draw Line segment FC — by Construction
Point G is the point of intersection between Line segment BE and Line segment FC — Intersecting Lines Postulate
Draw Line segment AG — by Construction
Point D is the point of intersection between Line segment AG and Line segment BC — Intersecting Lines Postulate
Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH — by Construction
__
II Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC — Midsegment Theorem
IV Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC — Substitution
I BGCH is a parallelogram — Properties of a Parallelogram (opposite sides are parallel)
III Line segment BD ≅ Line segment DC — Properties of a Parallelogram (diagonals bisect each other)
__
Line segment AD is a median Definition of a Median