I'm going to go right ahead and assume that we're talking about a linear equation.
The linear equation passing through the points given is y=3x+4, since it satisfies both of the points given.
Since the rate of descent is a constant this is a linear equation and can be expressed as:
h=vt+b, where h=feet, v=slope or rate, b=y-intercept (y value when x=0 which is the initial height)
h=-2t+b, using the point (3,67) we can solve for b, or the initial height
67=-2(3)+b
67=-6+b
73=b so the initial height was 73 ft and the height equation is then:
h(t)=67-2t so when t=8 you have:
h(8)=67-2(8)
h(8)=67-16
h(8)=51 ft
You would use the counting principal. 12X3X3
E=IZ=(3 + 2i)(<span>2 – i)=3*2-3i+2i*2-2i*i =6 - 3i+4i -2i²=6</span>-2i²- 3i+4i =6+2+i=8+i<span>
i²=-1
E=8+i</span>
