The drawing seems to suggest that angles BFA, AFE and EFD span a straight angle, just like angles BFC and CFD
This means that you have
But we know that both BFA and EFD measure 70 degrees, so the equation becomes
![[tex]70+AFE+70=180 \iff AFE + 140 = 180](https://tex.z-dn.net/?f=%20%5Btex%5D70%2BAFE%2B70%3D180%20%5Ciff%20AFE%20%2B%20140%20%3D%20180)
So, if you subtract 140 from both sides, you have
Abraham Lincoln djdjxu d d d d d d djdjsisow s susbs s s
The steps needed to solve the given equation is required.
Adding the opposite value of the constant to both sides.
Divide both sides by the coefficient of the variable.
The solution to the equation is
The given equation is
In order to solve this we first move constants to the side opposite of the variable.
This is done by adding the opposite value of the constant to both sides.
Here is the constant so we add to both sides.
Now, we divide both sides by the coefficient of the variable.
The solution to the equation is
