Since g(6)=6, and both functions are continuous, we have:
![\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2Bf%28x%29g%28x%29%5D%20%3D%2045%5C%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2B6f%28x%29%5D%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B9f%28x%29%5D%20%3D%2045%5C%5C%5C%5C9%5Ccdot%20lim_%7Bx%20%5Cto%206%7D%20f%28x%29%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20f%28x%29%3D5)
if a function is continuous at a point c, then
,
that is, in a c ∈ a continuous interval, f(c) and the limit of f as x approaches c are the same.
Thus, since
, f(6) = 5
Answer: 5
<span>12% = 12 percent = 12 parts out of 100 = 12/100</span>
<span>i hope thin helped
</span>
Answer:
-1
—— = -0.25000
4
Step-by-step explanation:
Tamam öğretmenim merhaba hocam nasılsınız iyi akşamlar canım çok sıkılıyo çok iyi bir insan bir arar bir şey var ama bir insan bir arar bir insan bir şey olmaz rica e evet w woorkbook woorkbook woorkbook woorkbook woorkbook woorkbook woorkbook woorkbook woorkbook woorkbook woorkbook woorkbook woorkbook we woorkbook woorkbook woorkbook evet w e okula bir insan
43 to 49 is 6
49 to 61 is 12
61 to 79 is 18
add 6 to each
79=4th row
79+18+6=79+24=103
103+24+6=103+30=133
133+30+6=133+36=169
7th row=169 seats
