Is this graph proportional?

(x−3)÷9=11 help idk how to do this

Bess [88]

Answer:

102

Step-by-step explanation:

papa math will help you

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

6 0

3 years ago

When we add polynomials, we _____ the coefficients but keep the ______ _______ the same

maxonik [38]

Answer:

When we add polynomials, we ADD the coefficients but keep the VARIABLES the same.

Step-by-step explanation:

"coefficients" are the numbers right next to a variable. "Variables" are the letters we use for unknown numbers in a math phrase(expression) or sentence(equation).

So you only add the number besides the variable when the terms have the same variable.

Example:

4x + 3m + 5x + 2m

= 9x + 5m

See we only added the 4 and the 5 bc they were both beside the x and we added the 3 and the 2 bc they were both beside the m. See image for another example.

7 0

2 years ago

At the beach 29% of people have red towels and 18% have white towels if the rest have blue ,what percentage of the people at the

Vikki [24]

The percent of people with blue towels would be the remaining percent when you add the red and wight towels together.
a.k.a
53% would have blue towels.

6 0

4 years ago

Which equations are equivalent to y = two-thirds x minus 4 when written in slope-intercept form? Check all that apply.

Nikitich [7]

Answer:

B an C is the answer

Step-by-step explanation:

I HOPE THIS HELPS!

I TOOK THE QUIZ ON Edge

5 0

3 years ago

Read 2 more answers

The amount of money spent on textbooks per year for students is approximately normal.

Contact [7]

Answer:

(A) A 95% confidence for the population mean is [$332.16, $447.84] .

(B) If the confidence level in part (a) changed from 95% to 99%, then the margin of error for the confidence interval would increase.

(C) If the sample size in part (a) changed from 19 to 22, then the margin of error for the confidence interval would decrease.

(D) A 99% confidence interval for the proportion of students who purchase used textbooks is [0.363, 0.477] .

Step-by-step explanation:

We are given that 19 students are randomly selected the sample mean was $390 and the standard deviation was $120.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $390

s = sample standard deviation = $120

n = sample of students = 19

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.101 < $t_1_8$ < 2.101) = 0.95 {As the critical value of t at 18 degrees of

freedom are -2.101 & 2.101 with P = 2.5%}

P(-2.101 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.101) = 0.95

P( $-2.101 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.101 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.101 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.101 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.101 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.101 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $\$390-2.101 \times {\frac{\$120}{\sqrt{19} } }$ , $\$390+2.101 \times {\frac{\$120}{\sqrt{19} } }$ ]

= [$332.16, $447.84]

(A) Therefore, a 95% confidence for the population mean is [$332.16, $447.84] .

(B) If the confidence level in part (a) changed from 95% to 99%, then the margin of error for the confidence interval which is $Z_(_\frac{\alpha}{2}_) \times \frac{s}{\sqrt{n} }$ would increase because of an increase in the z value.

(C) If the sample size in part (a) changed from 19 to 22, then the margin of error for the confidence interval which is $Z_(_\frac{\alpha}{2}_) \times \frac{s}{\sqrt{n} }$ would decrease because as denominator increases; the whole fraction decreases.

(D) We are given that to estimate the proportion of students who purchase their textbooks used, 500 students were sampled. 210 of these students purchased used textbooks.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion students who purchase their used textbooks = $\frac{210}{500}$ = 0.42

n = sample of students = 500

p = population proportion

Here for constructing a 99% confidence interval we have used a One-sample z-test statistics for proportions

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.42 -2.58 \times {\sqrt{\frac{0.42(1-0.42)}{500} } }$ , $0.42 +2.58 \times {\sqrt{\frac{0.42(1-0.42)}{500} } }$ ]

= [0.363, 0.477]

Therefore, a 99% confidence interval for the proportion of students who purchase used textbooks is [0.363, 0.477] .

8 0

3 years ago