Answer:
Step-by-step explanation:
Perimeter of a rectangle = 2(L +W)
Given L = W + 2 and the perimeter is greater than 112 meters?
P rect < 2(L +W) L = W + 2
P rect < 2(W + 2 +W)
< 2(2W+2)
112 < 4W + 4 solve for W
(112 - 4)/4 < (4W +4 - 4)/4
108/4 < (4W + 0)/4
27 < W
the width has to be greater than 27 meters
Total surface area is 152 cm
There’s probably an easier way to do it like with the equation to find the area of a trapezoid but i did it this way bc it’s easier for me
i split the trapezoid into a triangle and a square
with the pythagorean theorem i found the missing side length to find the area of the square (length X width)
then found the area of the triangle (base X height divided by 2)
THE ANSWER IS 68.9 CM
Answer: Add like terms
Step-by-step explanation:
For example, you would add 6x and 5x to make 11x, but there other two numbers you would leave alone.
<span>A.Two acute angles and two obtuse angles
Hope this helps!
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