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Elis [28]
3 years ago
11

A Statistics class has a test average of 87 with a standard deviation of 2.1. Find the z-score that corresponds to Kate's test s

core of 93. (Round to the nearest hundredths)
Mathematics
1 answer:
Leto [7]3 years ago
3 0

Answer:

2.86

Step-by-step explanation:

So I'm pretty sure we don't want the probability, just the zscore

to find the zsore subtract the mean and divide by the standard deviation

(93-87)/2.1= 2.86

You might be interested in
Evaluate g(x)=4−3x when x=−3, 0, and 5
Nikolay [14]

Answer:

13, 4, and -11

Step-by-step explanation:

g(-3)=4+9=13

g(0)=4+0=4

g(5)=4-15=-11

3 0
2 years ago
Job A -Sales- offers a base salary of $1,000 per week plus 3% commission on all sales above $3000. Job B -Sales- offers a base s
Ivahew [28]

Answer:

Job A pay <u>$25</u> than Job B.

Step-by-step explanation:

Given:

Job A -Sales- offers a base salary of $1,000 per week plus 3% commission on all sales above $3000.

Job B -Sales- offers a base salary of $1,100 per week plus 2.5% commission on all sales above $3000.

The total sales for the week equal $25,000.

Now, to find how much more money Job A pay than Job B.

Total sales = $25,000.

Job A pay:

Base salary = $1,000.

Base salary plus 3% commission on $25000.

$1000 + 3% of $25000.

= 1000+\frac{3}{100}\times 25000

=1000+0.03\times 25000

=1000+750

=1750.

Job A pay = $1750.

Now,

Job B pay:

Base salary = $1,100.

Base salary plus 2.5% commission on $25000.

$1,100 + 2.5% of $25,000.

=1100+\frac{2.5}{100}\times 25000

=1100+0.025\times 25000

=1100+625

=1725

Job B pay = $1725

So, by deducting the salary of Job B from Job A we get the more amount:

1750-1725\\=25

Therefore, Job A pay $25 than Job B.

6 0
3 years ago
A population mean of 360, a standard deviation of 4, and a margin of error of 2.5%
Ad libitum [116K]

Answer:

(351.04, 368.96)

Step-by-step explanation:

Given that population mean= 360

Std devitaion = 4

margin of error = 2.5%= 0.025

Since population std deviation is known we can use Z critical value

For two tailed critical value for 2.5% would be

2.24

Margin of error = ±Critical value*std deviation

= ±2.24(4)

= ±8.96

Confidence interval =(Mean - margin of error, mean + margin of error)

=(360-8.96, 360+8,.96)\\= (351.04, 368.96)

3 0
4 years ago
X + 1 and 1/4 = -5/8
slavikrds [6]
X + 1 = - 1/4 - 5/8
x + 1 = -2 - 5 / 8
x + 1 = - 7/ 8
x = -7 /8 - 1
x = - 7 - 8 / 8
x = - 15 / 8
4 0
3 years ago
Read 2 more answers
Can someone tell me how do I solve this. how is the result 2.40
liubo4ka [24]

Step-by-step explanation:

<u>Properties used</u>

  • logₐ a = 1
  • log aᵇ = b log a
  • log ab = log a + log b

See the steps below

  • - log (4*10⁻³) =
  • - (log 4 + log 10⁻³) =        (log 4 ≈ 0.6 rounded)
  • - (0.6 - 3*log 10) =
  • - (0.6 - 3*1) =
  • - (0.6 - 3) =
  • - (- 2.4) =
  • 2.4
6 0
2 years ago
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