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shepuryov [24]
3 years ago
9

What is the sum? 3 y / Y 2 + 7 y + 10 + 2 / y + 2​

Mathematics
1 answer:
kap26 [50]3 years ago
6 0

Answer:

  5/(y+5)

Step-by-step explanation:

Perhaps you want the sum ...

  \dfrac{3y}{y^2+7y+10}+\dfrac{2}{y+2}\\\\=\dfrac{3y}{(y+2)(y+5)}+\dfrac{2(y+5)}{(y+2)(y+5)}=\dfrac{3y+2(y+5)}{(y+2)(y+5)}\\\\=\dfrac{5y+10}{(y+2)(y+5)}=\dfrac{5(y+2)}{(y+2)(y+5)}=\boxed{\dfrac{5}{y+5}}

_____

<em>Comment on rational expressions</em>

When writing ratios in plain text, it is imperative to put parentheses around numerators and denominators. (If the numerator is a product only, then parentheses are optional.)

Your expression might be properly written as ...

  3y/(y^2 +7y +10) +2/(y+2)

As you have written it, it simplifies to ...

  3(y/y)2 +7y +10 +2/y +2 = 3·2 +7y +2/y +12

  = 7y +2/y +18

Please note, too, the exponentiation symbol (^).

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Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc
In-s [12.5K]

Answer:

\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

L^2 = y^2 + x^2

\implies L = \sqrt{y^2 + x^2},

Differentiating with respect to time (t),

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=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})

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Here,

\frac{dy}{dt}=-6\text{ ft per sec}

Also, \frac{dL}{dt} = 0           ( Ladder length = constant ),

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-6x + y\frac{dy}{dt}=0

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\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}

Which is the required notation.

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Step-by-step explanation:

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Step-by-step explanation:

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