All categories

3 years ago

I need some help ASSAPPP please

Mathematics

2 answers:

Sedaia [141]3 years ago

8 0

I cant see it sorry :(

Xelga [282]3 years ago

5 0

I’m not positive, but the only one that y has 4 in it is the 3rd one down with the mixed numbers so I’m guessing that one, lmk if it’s right or not!!

You might be interested in

47pts and brainliest <br> -55 − -37 =

jok3333 [9.3K]

Pretty sure it is -18...... Hope this helps

4 0

3 years ago

Read 2 more answers

How to find t=3,500•(1.10)^100, round to the nearest whole number

VMariaS [17]

Answer:

To find 3,500 by near to 3,550

Step-by-step explanation:

the nearest number of 3,500 is 3,500

5 0

3 years ago

Use the interactive number line to find the difference. 4.7 - 2.3 = 4.7 + (-2.3) =

FromTheMoon [43]

Answer:

Arrow from 0 to 4.7 and from 4.7 to 2.4

Step-by-step explanation:

4.7 is also 0+4.7

arrow from 0 to 4.7.

-2.3 from 4.7 is 4.7-2.3=2.4

arrow from 4.7 to 2.4.

5 0

3 years ago

Please I need to know if its true or false please lmk!!!

Papessa [141]

Answer:

False

Step-by-step explanation:

<u>According to the complex conjugate root theorem:</u>

if a complex number is a root of a polynomial, its conjugate is also the root of the polynomial

We are given all the roots of the polynomial and there is only one complex root

Since according to the complex conjugate root theorem, there can be either none or at least 2 complex roots of a polynomial

We can say that this set of roots of a polynomial is incorrect

7 0

3 years ago

Read 2 more answers

AHHHHH! IM FREAKING OUT I NEED HELP NOW AND I WILL MARK BRAINLEST!!!! Question :

Andreas93 [3]

Answer:

Step-by-step explanation:

if i can draw, then i can explain better

distance between centers=r+3r=4r

we have to find the side of a right angled triangle by pythagoras theorem

given hypotenuse=4r

and one side=3r-r=2r

$d=\sqrt{(4r)^2-(2r)^2} =\sqrt{12r^2}=2\sqrt{3}r\\$

this is the distance if they touch.

but if they are r distance apart

then distance between centers=r+r+3r=5r

so hypotenuse=5r

length of tangent

$=\sqrt{(5r)^2-(2r)^2} \\=\sqrt{21r^2} \\=\sqrt{21} r$

3 0

3 years ago